Regex匹配Telegram用户名并删除PHP中的整行

Question

我想在消息文本中匹配Telegram用户名并删除整行，我尝试过这种模式，但问题是它也匹配电子邮件：

.*(@(?=.{5,64}(?:s|$))(?![_])(?!.*[_]{2})[a-zA-Z0-9_]+(?<![_.])).*

图案应匹配所有这些行：

你好@username你好吗？

你好@username.你好吗？

😉@用户名。

并且不应该像这样匹配电子邮件：

嗨，发送电子邮件至[e-mail]

Answer 1

使用

.*B@(?=w{5,32}b)[a-zA-Z0-9]+(?:_[a-zA-Z0-9]+)*.*

查看验证

@之前的B意味着在@之前必须有一个非单词字符或字符串的开头。

解释

NODE                     EXPLANATION
--------------------------------------------------------------------------------
.*                       any character except n (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
B                       the boundary between two word chars (w)
or two non-word chars (W)
--------------------------------------------------------------------------------
@                        '@'
--------------------------------------------------------------------------------
(?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
w{5,32}                 word characters (a-z, A-Z, 0-9, _)
(between 5 and 32 times (matching the
most amount possible))
--------------------------------------------------------------------------------
b                       the boundary between a word char (w)
and something that is not a word char
--------------------------------------------------------------------------------
)                        end of look-ahead
--------------------------------------------------------------------------------
[a-zA-Z0-9]+             any character of: 'a' to 'z', 'A' to 'Z',
'0' to '9' (1 or more times (matching the
most amount possible))
--------------------------------------------------------------------------------
(?:                      group, but do not capture (0 or more times
(matching the most amount possible)):
--------------------------------------------------------------------------------
_                        '_'
--------------------------------------------------------------------------------
[a-zA-Z0-9]+             any character of: 'a' to 'z', 'A' to
'Z', '0' to '9' (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
)*                       end of grouping
--------------------------------------------------------------------------------
.*                       any character except n (0 or more times
(matching the most amount possible))

Answer 2

.*[W](@(?=.{5,64}(?:s|$))(?![_])(?!.*[_]{2})[a-zA-Z0-9_]+(?<![_.])).*

我在@symbol之前添加了这个[W]非单词字符。在这里你可以查看结果https://regex101.com/r/yFGegO/1

Answer 3

阳光下没有什么新鲜事，但基本上其他模式可以简化为：

.*?B@w{5}.*

演示

或者最终：

.*?Bw{5,64}b.*

如果你想更精确，但它真的需要吗？

注意：如果您也想删除换行序列，请在模式末尾添加R?。