按距离过滤来自2个输入的许多X|Y坐标

Question

我想按距离过滤许多坐标，但我不能用另一个来计算二维表的每个元素。我已经将格式从文本更改为二维数组，其中每个元素都是一个坐标，其中有X和Y。我不能全部解释，但我有一个小提琴项目，它清楚地显示了出来。

结果我想得到的是一个来自textfield1的坐标列表，对于来自textfield2 的每个坐标，它们的距离都不超过5

请查看：https://jsfiddle.net/Ashayas/9c7mjts4/

console.log("==== 1 ====");
//Get inputs
var coords1 = document.getElementById("coord1").value.split(" ");
var coords2 = document.getElementById("coord2").value.split(" ");
console.log(coords1);
console.log(coords2);
console.log("==== 2 ====");
//Make them X and Y
var coords1_intoXY = [];
for (var i = 0; i < coords1.length; i++) {
coords1_intoXY[i] = coords1[i].split("|");
}
var coords2_intoXY = [];
for (var i = 0; i < coords2.length; i++) {
coords2_intoXY[i] = coords2[i].split("|");
}
console.log(coords1_intoXY);
console.log(coords2_intoXY);
//Now combine all x|y and put into new array, after that sort and get result
//I dont know is that good thinking, maybe there is another way to achieve result
/*
var beforesort = [];
for (var i = 0; i < originalContent.length; i++) {
paste7[i] = originalContent[i].join(" ").split(splitCharacter).filter(x => !unwantedContent.includes(x));
}
function compare(coords1,coords2){
const coords3 = [];

let result;

coords1.forEach((e1,i)=>coords2.forEach(e2=>{

if(e1.length > 1 && e2.length){
result = compare(e1,e2);
}else if(e1 !== e2 ){
result = false
}else{
result = true
}
})
)

return result

}
*/
x1 = 10
y1 = 10
x2 = 1
y2 = 1
example = Math.hypot(x2 - x1, y2 - y1)
console.log("Example = " + example);
function distance(x1, y1, x2, y2) {
a = Math.abs(Number(x1 - x2));
b = Math.abs(Number(y1 - y2));
c = Math.sqrt((a * a) + (b * b));
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
Program sort coordinates X|Y from inputs. Result is a list of coordinates from input1 which their distances between second input coords arent highter than the value from input 3 (for example "5")
<br>
<br> Two inputs for coordinates X|Y
<br>
<textarea id="coord1">3|1 5|5 10|10</textarea>
<textarea id="coord2">9|1 1|1</textarea>
<br> Sort by max distance
<br>
<input value="5" id="coord3">
<br>
<br>
<textarea id="result">Result</textarea>
<br>
<button id="show">Show</button>
<br>
<br> EXAMPLE:
<br>
<br> We have "3|1 5|5 10|10" inside coord1
<br> We have "9|1 1|1" inside coord2
<br>
<br> Program calculate distance between coords
<br> 3|1 and 9|1 = 6
<br> 3|1 and 1|1 = 2
<br> 5|5 and 9|1 = 5.65 ~ 6
<br> 5|5 and 1|1 = 5.65 ~ 6
<br> 10|10 and 9|1 = 9.05 ~ 9
<br> 10|10 and 1|1 = 12.72 ~ 13
<br>
<br> And the result should looks like this:
<br> 3|1
<br> Other coords are higter than 5 distance in any case so we skip them
<br>
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>>>想象一下它的外观<lt<

我需要它用于学校项目，并想为未来学习，所以代码之间的注释会很棒！

Answer 1

我不确定你是否想要一个来自textfield1的坐标列表，对于来自textfield2的所有坐标，它们的距离都不大于5，或者只是来自textfield 2的任何坐标。无论哪种方式，代码都非常相似。

您想要筛选出不符合某些条件的值，所以我们从方法filter开始

coords1_intoXY.filter()

那么标准是什么呢？我假设文本字段2上所有数字的距离必须小于5，因此我们需要every

coords1_intoXY.filter(coords1 => coords2_intoXY.every())

请注意，如果您想要的坐标在文本字段2中任何坐标的范围内，只需将every替换为some

现在，正如奥利弗所说，我们计算距离。

var coords1_intoXY = [["3", "1"], ["5", "5"], ["10", "10"]];
var coords2_intoXY = [["9", "1"], ["1", "1"]];
let answer = coords1_intoXY.filter(coords1 => coords2_intoXY.some(coords2 => {
let x = Number(coords1[0]) - Number(coords2[0])
let y = Number(coords1[1]) - Number(coords2[1])
return Math.hypot(x, y) < 5
}))
console.log(...answer.map(coords => coords.join('|')));

对于最后一部分，按照您的意愿显示

return answer.map(coords => coords.join('|'));