我正在尝试部署云功能来在firebase(Firestore(上创建推送通知(聊天消息(。但当我尝试这样做时，我总是收到HTTP错误：400，请求有错误。看起来收集的路径很好。
exports.notifyNewMessage = functions.firestore
.document('/chat/{toUserId}/chatRoom/{fromUserId}/chatItems')
.onCreate((docSnapshot, context) => {
const message = docSnapshot.data();
const recipientId = context.params.toUserId; // получатель сообщения
const senderId = context.params.fromUserId; // отправитель сообщения
const senderName = message['username'];
if (recipientId === senderId) {
} else {
return admin.forestore().doc('tokens/' + recipientId).get().then(userDoc => {
const tokens = userDoc.get('tokens')
const notificationBody = (message['type'] === "TEXT") ? message['textMessage'] : "New message with Image"
const payload = {
notification: {
title: senderName + " sent you a message",
body: notificationBody,
clickAction: "ChatActivity" // возможно, это только для андроида
},
data: {
USER_NAME: senderName,
USER_ID: message['senderId']
}
}
return admin.messaging().sendToDevice(tokens, payload).then( response => {
const stillRegisteredTokens = tokens
response.results.forEach((result, index) => {
const error = result.error
if (error) {
const failedRegistrationToken = tokens[index]
console.error('failed token', failedRegistrationToken, error)
if (error.code === 'messaging/invalid-registration-token' || error.code == 'messaging/registration-token-not-registred') {
const failedIndex = stillRegisteredTokens.indexOf(failedRegistrationToken)
if (failedIndex > -1) {
stillRegisteredTokens.splice(failedIndex, 1)
}
}
}
})
return admin.firestore().doc("tokens" + recipientId).update({
tokens: stillRegisteredTokens
})
})
})
}
})
我也会问关于"；单击操作："聊天活动"；它只适用于android？我怎么能对ios做同样的事情？太多了！
尝试从firebase控制台删除函数并重新部署
或
尝试更改Internet服务提供商并部署