我正在尝试从两个表中进行选择。我有两张桌子:
select * from igw41_users;
+-----+------------+----------+-----------------------------+--------------------------------------------------------------+-------+-----------+---------------------+---------------------+------------+--------------------------------------------------------------------------------------------------------------------------------+---------------------+------------+--------+------+--------------+
| id | name | username | email | password | block | sendEmail | registerDate | lastvisitDate | activation | params | lastResetTime | resetCount | otpKey | otep | requireReset |
17 John Doe AAAAAA nothing else is needed from this table.
select * from igw41_user_profiles;
+---------+----------------------+-----------------------+----------+
| user_id | profile_key | profile_value | ordering |
17 profile.account_type "2" 4
17 profile.postal_code "75055" 1
我需要获取id(来自igw41_users(、用户名igw41_users、postal_code(来自igw 41_user_profiles(和account_type。但是,我需要的信息是每个igw41_user_profiles.user_id的profile_values中与igw41_users.id匹配的信息。
select id, username, GROUP_CONCAT(profile_value SEPARATOR ',')
from igw41_users
left join igw41_user_profiles on igw41_users.id = igw41_user_profiles.user_id and igw41_user_profiles.profile_key = 'profile.account_type'
group by username;
这给了我account_type,但我不知道如何获得postal_code。如果我进行了正确的联接,它会给我:错误1066(42000(:不是唯一的表/别名:'igw41_user_profiles'
这就是我试图获得的两个配置文件值:
select id, username, GROUP_CONCAT(profile_value SEPARATOR ',')
from igw41_users
left join igw41_user_profiles on igw41_users.id = igw41_user_profiles.user_id and igw41_user_profiles.profile_key = 'profile.account_type'
right join igw41_user_profiles on igw41_users.id = igw41_user_profiles.user_id and igw41_user_profiles.profile_key = 'profile.postal_code'
group by username;
提前谢谢。
take和igw41_user_profile.profile_key='profile.account_type'退出您的第一个查询
如果你想在中测试两者的使用
and igw41_user_profiles.profile_key in('profile.account_type','profile.postal_code')
通常情况下,当您需要多次加入同一个表时,每次加入都需要使用别名:
select id, username, GROUP_CONCAT(profile_value SEPARATOR ',')
from igw41_users
left join igw41_user_profiles p1
on igw41_users.id = p1.user_id and
p1.profile_key = 'profile.account_type'
right join igw41_user_profiles p2
on igw41_users.id = p2.user_id and
p2.profile_key = 'profile.postal_code'
group by username;
在这种情况下,第二个连接是多余的:
select id, username, GROUP_CONCAT(profile_value SEPARATOR ',')
from igw41_users
left join igw41_user_profiles p1 on igw41_users.id = p1.user_id
where
p1.profile_key = 'profile.account_type' OR
p1.profile_key = 'profile.postal_code'
group by username;