如何访问xmlns命名空间Web服务中的请求响应

Question

有一个web服务返回类似的内容，我想在此响应中访问id。我该怎么办？

<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/">{"id":"1819","responseCode":"0","responseMessage":"0"}</string>

另外，我的功能在这里：

import requests
def sen_request():
url = "somewhere.com/somewhere.asmx/new_one"
payload = {}
headers= {}
response = requests.request("GET", url, headers=headers, data = payload)
return (response)

• 我试图用response.JSON((访问JSON中的响应，但符合此错误：

Exception Type:   JSONDecodeError
Exception Value: Expecting value: line 1 column 1 (char 0)

Answer 1

代码使用json-lib和XML-lib解析来提取id

import json
import xml.etree.ElementTree as ET
data = '''<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/">{"id":"1819","responseCode":"0","responseMessage":"0"}</string>'''
data1 = '''<?xml version="1.0" encoding="utf-8"?><string xmlns="tempuri.org">{"id":{"id1":"1819"},"responseCode":"0","responseMessage":"0"}</string>'''
root = ET.fromstring(data)
print(json.loads(root.text)['id'])
root = ET.fromstring(data1)
print(json.loads(root.text)['id']['id1'])

输出

1819
1819