我正在Scala中学习函数式编程,但我做不到。
def lel2(bids: List[Double], vols: List[Double]): Image = {
bids.size match {
case 0 => Image.empty
case n => Image.triangle(asks(n-1), vols(n-1))
.transform(Transform.rotate(180.degrees)).above(lel2(bids.init, vols.init))
}
}
唯一的依赖是"org.creativescala" %% "doodle" % "0.9.20"
,而导入是import doodle.core._; import doodle.image._; import doodle.image.syntax._; import doodle.image.syntax.core._; import doodle.java2d._
我想做的是输出三角形的旋转图像,如果这是正确的术语,则水平翻转:(
我也使用这个List[Double]
的:
List[Double] = List(9.963005799312612, 9.964236205100441, 9.96497444857314, 9.972931072667766, 9.97317715382533, 9.979821345079607, 9.988352158541886, 10.0)
List[Double] = List(0.5617977528089887, 0.42134831460674155, 4.213483146067415, 0.5168539325842696, 0.5168539325842696, 2.6235955056179776, 2.1067415730337076, 10.0)
相关链接:
转换文档
CreativeScala书籍
涂鸦模块
您应该在Image.triangle(x, xx)
周围加上另一个括号,以将其转换为
(Image.triangle(bids(n-1), vols(n-1))).transform(Transform.rotate(180.degrees))