为什么我不能循环 xmltodict？

Question

Ive’being try to transform all log in a dict through xmltodict.parse function

问题是，当我试图将单行转换为变量时，效果很好

a=xmltodict.parse(df['CONFIG'][0](

与相同

parsed[1]=xmltodict.parse(df['CONFIG'][1](

但是，当我尝试迭代整个数据帧并将其存储在dictionaire上时，我会得到以下

for ind in df['CONFIG'].index:
parsed[ind] = xmltodict.parse(df['CONFIG'][ind])
---------------------------------------------------------------------------
ExpatError                                Traceback (most recent call last)
/tmp/ipykernel_31/1871123186.py in <module>
1 for ind in df['CONFIG'].index:
----> 2      parsed[ind] = xmltodict.parse(df['CONFIG'][ind])
/opt/conda/lib/python3.9/site-packages/xmltodict.py in parse(xml_input, encoding, expat, process_namespaces, namespace_separator, disable_entities, **kwargs)
325         parser.ParseFile(xml_input)
326     else:
--> 327         parser.Parse(xml_input, True)
328     return handler.item
329 
ExpatError: syntax error: line 1, column 0

Answer 1

你能试试这个吗？

for ind in range(len(df['CONFIG'])):
parsed[ind] = xmltodict.parse(df['CONFIG'][ind])