蓝牙低能耗简单代码，发现时出错()

Question

我正在尝试使用python3 ble.py:运行下一个代码

import asyncio
from bleak import discover
async def run():
devices = await discover()
for d in devices:
print(d)
loop = asyncio.get_event_loop()
loop.run_until_complete(run())

看看有多少可用的设备，但我得到了这个错误：

Traceback (most recent call last):
File "ble.py", line 10, in <module>
loop.run_until_complete(run())
File "/usr/lib/python3.7/asyncio/base_events.py", line 584, in run_until_complete
return future.result()
File "ble.py", line 5, in run
devices = await discover()
File "/home/pi/.local/lib/python3.7/site-packages/bleak/backends/bluezdbus/discovery.py", line 173, in discover
).asFuture(loop)
txdbus.error.RemoteError: org.freedesktop.DBus.Error.AccessDenied: Rejected send message, 2 matched rules; type="method_call", sender=":1.21" (uid=1000 pid=1170 comm="python3 ble.py ") interface="org.freedesktop.DBus.ObjectManager" member="GetManagedObjects" error name="(unset)" requested_reply="0" destination="org.bluez" (uid=0 pid=442 comm="/usr/lib/bluetooth/bluetoothd ")

我不明白这个错误的意思，我是不是遗漏了什么？

Answer 1

对于有同样问题的人，将用户添加到蓝牙组解决了问题。