如果匹配字符串，则递增else继续意思是如果x=["你"，"我"，"我们"，"然后"]和y=["嗨"，"国王"，"你"、"你"注意：如果代码和您匹配一次，就不应该停止它应该搜索到元素的末尾吗？
x = ["you","me","us","then"]
y = ["hi","king","you","you","thai","you"]
word_count = {}
for each_word in x :
word_count[each_word] = y.count(each_word)
print(dict)
#result : {'you': 3, 'me': 0, 'us': 0, 'then': 0}
如果这不是你想要的答案，请提供你期望的样本结果来解释这个问题。