我应该如何格式化输出

Question

对于这段代码，我需要能够打印输出，但我不确定如何完成这项任务。我根本无法更改主函数，并且我正在寻找某个输出。预期的输出应该格式化为小部件名称、ID，然后是小部件的地址。我想我可以使用字符串作为输出，但我不确定如何实现它。
主.cpp是

#include <iostream>
#include <string>
#include "widget.h"
using namespace std;
int main()
{
//makes three widgets using the regular constructor
const Widget weather( WEATHER );
const Widget quote( QUOTE );
const Widget stock( STOCK );

cout << "weather widget 1: " << weather.getModelName() << endl;
cout << "quote widget 1: " << quote.getModelName() << endl;
cout << "stock widget 1: " << stock.getModelName() << endl;

//makes three widgets using the copy constructor
Widget weather2 = weather;
Widget quote2 = quote;
Widget stock2 = stock;

cout << "weather widget 2: " << weather2.getModelName() << endl;
cout << "quote widget 2: " << quote2.getModelName() << endl;
cout << "stock widget 2: " << stock2.getModelName() << endl;

cin.get();

return 0;

}

小部件.h是

#include <string>
using namespace std;
enum WidgetType
{
INVALID_TYPE = -1,
WEATHER,
QUOTE,
STOCK,
NUM_WIDGET_TYPES
};

const string WIDGET_NAMES[NUM_WIDGET_TYPES] = { "Weather2000",
"Of-The-Day",
"Ups-and-Downs"
};

class Widget
{
public:
Widget( WidgetType type );
//add copy constructor
Widget( const Widget& rhs );
string getModelName() const { return wModelName; };
WidgetType getType() {return wType;};

private:
WidgetType wType;
int wID;
string wModelName;
static int userID;
//add static data member

void generateModelName();
};

那么小工具.cpp就是

#include "iostream"
#include "widget.h"
int Widget::userID = 1;
Widget::Widget( WidgetType type )
{
wID = userID;
wType = type;
wModelName = wType;
userID++;
generateModelName();
}
Widget::Widget( const Widget& rhs )
{
wID = userID;
wType = rhs.wType;
wModelName = wType;
userID++;
generateModelName();
}
void Widget::generateModelName()
{
if (getType() == WEATHER)
{
wModelName = "Weather2000";
}
else if (getType() == QUOTE)
{
wModelName = "Of-The-Day";
}
else if (getType() == STOCK)
{
wModelName = "Ups-and-Downs";
}
}

最后，预期的结果是

weather widget 1:       Weather2000    1  000000145FD3F628
quote widget 1:         Of-The-Day     2  000000145FD3F678
stock widget 1:         Ups-and-Downs  3  000000145FD3F6C8
weather widget 2:       Weather2000    4  000000145FD3F718
quote widget 2:         Of-The-Day     5  000000145FD3F768
stock widget 2:         Ups-and-Downs  6  000000145FD3F7B8

Answer 1

您可以更改getModelName以在std::ostringstream的帮助下生成所需的输出。

旧实现：

string getModelName() const { return wModelName; };

新版本：

#include <sstream> // std::ostringstream
string getModelName() const {
std::ostringstream os;
os << 't' << wModelName << 't' << wID << "  " << std::hex << this;
return os.str();
};

演示