f = open('wordlist.txt','w')
for x in range(4):
u = input('please enter how many words you like to write')
f.write(u + 'n')
print('it have been wrote into file')
e = 0
y = 0 #y for total length
f = open('wordlist.txt','r')
for x in f:
print(len(x))
y += len(x)
e += 1
if len(x) >= len(x):
z = len(x) #get largest length
avglength = y/e #get average length for each line
print(z)
print(y)
print(avglength)
正如上面的代码，我想得到文件中最大的长度，但它只得到最后一个单词的长度，为什么会发生这种情况？以及如何删除每个字符串后面的'\n'，我需要找到每个单词的长度，但长度不正确。例如，"ss"的长度应该为3，在我的代码中，我添加了每行"\n"，这可能会导致"ss"长度为4。有什么帮助吗？
您在代码中写入：
if len(x) >= len(x):
z = len(x)
其将始终是CCD_ 1。因此，您的z将取上一个x的长度值，这将是您的最后一个单词。
您可以通过在for循环之外定义一个max_length变量来跟踪当前的最大长度：
max_length = 0
和在环使用：
max_length = max([len(x), max_length])
if len(x) >= max_length:
z = len(x)
max_length = z
或者，正如你在下面的评论中指出的那样，你可以简单地将整个声明写成：
z = max([len(x), z])
前提是您已将z = 0设置在for循环之外。
这里有一个稍微修改过的计算方法。它可能更容易阅读，并且它使用上下文管理器with来处理打开和关闭文件：
# get words and write to file
with open('wordlist.txt','w') as f:
for x in range(4):
u = input('please enter a word: ')
f.write(u + 'n')
print('Your words have been written into the file')
# read words and count find length of longest word
with open('wordlist.txt') as f:
words = f.readlines()
word_lengths = [len(i.strip()) for i in words] # get the length of each word in list after removing white space
max_length = max(word_lengths) # find the longest length
total_length = sum(word_lengths) # find the total length of all words
average_word_length = total_length / len(words) # find the average length
您可以使用.split()方法从字符串中删除n。
以下是你必须做的：
x = x.split('n')
x = x[0]
您可以将其添加到True0循环中。
这是完整的代码：
f = open('wordlist.txt', 'w')
for x in range(4):
u = input('Please enter the word: ')
f.write(u + 'n')
print('it has been written into file')
z = 0
e = 0
y = 0 # y for total length
f = open('wordlist.txt', 'r')
for x in f:
x = x.split('n') #Now, x = ['Your Input', '']
x = x[0] #Select first string
print(len(x))
y += len(x)
e += 1
if len(x) >= z:
z = len(x) # get largest length
avglength = y / e # get average length for each line
print(z)
print(y)
print(avglength)
这是运行：
Please enter the word: This
Please enter the word: is
Please enter the word: just
Please enter the word: testing
各自的输出：
4
2
4
7
7
17
4.25
另一种可能的解决方案：
# Use open() as a context manager so you don't have to worry about closing the file.
with open('wordlist.txt','r') as opened:
# Create a list of words in the file.
# words = list(opened)
# EDIT: The traditional way to split some lines and strip
# the newline character.
words = opened.read().strip().split("n")
# Start max_length at negative 1.
max_length = -1
# List object to hold all word lengths.
all_lengths = []
# Number of words written to file
num_of_words = len(words)
# Iterate the list of words.
for word in words:
# Get length of the current word.
current_length = len(word)
# Append the length of the current word to the list.
all_lengths.append(current_length)
# Using all_lengths[-1] gets the latest item on the list
# Also, we only care if the current value is larger than the max value.
if all_lengths[-1] > max_length:
max_length = all_lengths[-1]
# Average length of word per line.
average_length = sum(all_lengths) / num_of_words