conda环境使用/调用不正确的python版本

Question

我试图找到像这里这样的答案，但它们对我不起作用。

我有一个名为py36的python3.6环境。如果Iconda activate py36，然后用运行烧瓶

export FLASK_APP=main.py
flask run --port=5050

我得到以下错误：

Traceback (most recent call last):
File "/Users/USERNAME/anaconda/bin/flask", line 6, in <module>
sys.exit(flask.cli.main())
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 513, in main
cli.main(args=args, prog_name=name)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 380, in main
return AppGroup.main(self, *args, **kwargs)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/core.py", line 697, in main
rv = self.invoke(ctx)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/core.py", line 1066, in invoke
return _process_result(sub_ctx.command.invoke(sub_ctx))
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/core.py", line 895, in invoke
return ctx.invoke(self.callback, **ctx.params)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/core.py", line 535, in invoke
return callback(*args, **kwargs)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/decorators.py", line 64, in new_func
return ctx.invoke(f, obj, *args[1:], **kwargs)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/click/core.py", line 535, in invoke
return callback(*args, **kwargs)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 423, in run_command
app = DispatchingApp(info.load_app, use_eager_loading=eager_loading)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 152, in __init__
self._load_unlocked()
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 176, in _load_unlocked
self._app = rv = self.loader()
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 237, in load_app
rv = locate_app(self.app_import_path)
File "/Users/USERNAME/anaconda/lib/python3.5/site-packages/flask/cli.py", line 90, in locate_app
__import__(module)
File "/Users/USERNAME/Documents/Google_Drive/Projects/project/main.py", line 3, in <module>
import MySQLdb
ImportError: No module named 'MySQLdb'

问题不在于没有安装"MySQLdb"，因为它是在那种环境下安装的。

如果我做conda list，我会得到

mysql-connector-c         6.1.11               h42a37c1_0  
mysqlclient               1.4.6            py36h0a44026_0  

这证实了mysql安装在这个环境中。

如果我运行python，我会得到

$ python
Python 3.6.1 |Anaconda custom (64-bit)| (default, May 11 2017, 13:04:09) 
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.57)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> 

这证实了默认的python是3.6。

正如你所看到的，一切都应该是python3.6，但由于某种原因，错误来自我的python代码，它启动了python3.5而不是python36。我没有任何前缀或任何头来告诉它应该运行哪个python。

事实上，这是我主要.py 的顶部

from flask import Flask, request, render_template, jsonify
from flask_cors import CORS
from flask_pymongo import PyMongo
import MySQLdb
import json
import math
import pandas as pd
import numpy as np
from collections import OrderedDict
import pprint
import sys
app = Flask(__name__)
cors = CORS(app, resources={r"/*": {"origins": "*"}})

换句话说，我的conda环境本应安全地包含一个python版本(python 3.6(，但却未能不一致地激活正确的python版本。

我害怕修改路径，但如果我echo $PATH，这就是我得到的

>>>echo $PATH
/Users/USERNAME/anaconda/envs/py36/bin:/usr/local/opt/openssl/bin:/usr/local/opt/openssl/bin:/usr/local/opt/openssl/bin:/usr/local/opt/openssl/bin:/usr/local/fsl/bin:/Users/USERNAME/anaconda/bin:/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/opt/X11/bin:/usr/local/git/bin:/Library/Frameworks/Mono.framework/Versions/Current/Commands

我修复它的唯一方法是，如果我做了以下操作：

conda activate /Users/USERNAME/anaconda
pip install pymysql

虽然这解决了我的问题，但它只是一个创可贴，并不能解决问题。因为当我conda activate py36时，基本环境不是我想要使用的环境。

如有任何帮助，我们将不胜感激！

谢谢！

Answer 1

我的建议是重新创建您的虚拟环境。

让我们创建一个全新的虚拟环境(为了好玩，我们称之为appleslice(：

首先，通过执行deactivate，确保您当前没有在任何虚拟环境中运行。然后运行这个：

conda create --name appleslice python=3.6

然后执行：activate appleslice并继续安装所有需要的软件包。

如果仍然停滞不前，请看一看这篇文章。