如何在c++中读取短int(2字节)LSB第一个值?

Question

如何先用LSB读取两个单独的字节?

2个独立的LSB首字节->1 short int MSB first

。0100110011001100→00110010 00110011

short int lsbToMsb(char byte1, char byte2) {
...
return msb;
}

Answer 1

试试这个:

char reverseBits(char byte)
{
char reverse_byte = 0;
for (int i = 0; i < 8; i++) {
if ((byte & (1 << i)))
reverse_byte |= 1 << (7 - i);
}
return reverse_byte;
}
short int lsbToMsb(char byte1, char byte2) {
byte1 = reverseBits(byte1);
byte2 = reverseBits(byte2);
short int msb = (byte1 << 8) | byte2;
return msb;
}
int main(){
char byte1 = 76;    // 01001100
char byte2 = -52;   // 11001100
short int msb = lsbToMsb(byte1, byte2);
printf("%d", msb);

}

输出:

12851   // 00110010 00110011