如何触发石英作业从休息控制器在弹簧启动应用程序?

Question

我有一个控制器，我试图立即触发新的工作:

@GetMapping("/job/{tripId}")
public void handle(@PathVariable("tripId") Integer fundId) {        

SchedulerFactory schedFact = new org.quartz.impl.StdSchedulerFactory();
try {
Scheduler sched = schedFact.getScheduler();               
//Create a new Job 
JobKey jobKey = JobKey.jobKey("Trip Calculations", "Trip Calculations Group");
JobDetail job = JobBuilder.newJob(TripCalculationsJob.class).withIdentity(jobKey).storeDurably().build();
job.getJobDataMap().put("tripId", fundId);                      
//Register this job to the scheduler
sched.addJob(job, true);
sched.triggerJob(jobKey);

} catch (SchedulerException e) {
log.error("Error when execting job");
e.printStackTrace();
}                             

}

job是实现job的简单类:

@Slf4j
public class TripCalculationsJob implements Job {

public void execute(JobExecutionContext context) throws JobExecutionException {

log.info( "blah blah blah");
}

作业没有被触发，下面是maven的依赖项:

<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-quartz</artifactId>         
</dependency>
<dependency>
<groupId>org.quartz-scheduler</groupId>
<artifactId>quartz</artifactId>
</dependency>

Answer 1

我认为调度作业的全部意义在于不要手动触发它们。为什么不将作业的操作提取到另一个处理程序类中，并从作业和控制器中调用该处理程序?