我试图将以下for循环应用于列表per_d中的每个矩阵，并创建一个名为per_hole的新列表。我不知道怎么做，我应该用lapply吗?
提前感谢您的帮助!
per_hole <- per_d
for (i in 1:S) {
for (j in 1:t){
if (per_hole [i,j] > CS) {
per_hole [i,j] <- per_hole [i,j] - rnorm (1, mean = 1, sd = 0.5)
} else {
per_hole [i,j] <- per_hole [i,j] + rnorm (1, mean = 1, sd = 0.5)
}}}
复制代码
N <- 1
CS <- 10.141
S <- seq (7.72,13,0.807)
t <- 15
l <- length (S)
m0 <- 100
exps <- c(0.2, 0.5, 0.9, 1.5, 2)
sd_per <- c(0.2, 0.5, 0.8, 1.3, 1.8)
sd_noise <- 3
per <- lapply(sd_per, function(x){
per <- matrix(nrow = length(S)*N, ncol = t+1)
for (i in 1:dim(per)[1]) {
for (j in 1:t+1){
per [,1] <- replicate (n = N, S)
per [i,j] <- round (abs (rnorm (1, mean = per[i,1], sd =x)),digits=3)
colnames(per) <- c('physical',paste('t', 1:15, sep = ""))
per <- as.data.frame (per)
}
}
per <- per [,-1]
return(per)
}
)
names(per) <- paste("per", seq_along(sd_per), sep = "")
per_d <- lapply(per, function(x){
per_d <- abs (x - 10.141)
}
)
names(per_d) <- paste("per_d", seq_along(sd_per), sep = "")
你可以试试
per_hole <- lapply(per_d,function(x) x + ifelse(x>CS,-1,1)*rnorm(prod(dim(x)),1,0.5))
或
per_hole <- lapply(per_d, function(x) x + rnorm(prod(dim(x)), 1-2*(x > CS), 0.5))