TypeError:传递给Series.__format__的不支持格式字符串

Question

我试图以12小时时钟格式打印时间，但django抛出TypeError。在python中工作正常，但在django中显示错误Thanks is Advance

def solve(s, n):
h, m = map(int, s[:-2].split(':'))
h =h% 12
if s[-2:] == 'pm':
h =h+ 12
t = h * 60 + m + n
h, m = divmod(t, 60)
h =h% 24
if h < 12:
suffix = 'a' 
else:
suffix='p'
h =h% 12
if h == 0:
h = 12
return "{:02d}:{:02d}{}m".format(h, m, suffix)
solve('10:00am',45)

返回10:45am

Answer 1

就像我说的，使用strftime来做这些繁琐的工作，而不是自己做。

from datetime import datetime, timedelta

def solve(s, minutes):
time_instance = datetime.strptime(s, '%I:%M%p')
time_instance += timedelta(minutes=minutes)
return time_instance.strftime('%I:%M%p').lower()

print(solve('10:00am', 45))  # 10:45am
print(solve('10:00pm', 45))  # 10:45pm
print(solve('11:30pm', 45))  # 12:15am
print(solve('11:30pm', 120))  # 01:30am