从10开始的数字反转模式.(模式)的问题

Question

这就是我要打印的图案。

1
3 2
6 5 4
10 9 8 7

现在我有一个解决方案，但我不知道如何完全正确。

解决方案:

length = 6
start = 1
stop = 2
currentNumber = stop
for row in range(stop, length):
for col in range(start, stop):
currentNumber -= 1
print(currentNumber, end=" ")
print(" ")
start = stop
stop += row
currentNumber = stop

我认为它是这样工作的:

# for row in range(2, 6): 2, 3, 4, 5,
# for col in range(1, 2):
#  currentnum = 2-1 = 1
#  print( 1 )
#  start = stop (start = 2)
#  stop += 2 (row = 2,3,4,5) so now stop = 2 + 2 = 4
# currentNumber = 4
# for row in range(4, 6): 4,5
# for col in range(2, 4): 2, 3 means 2 time will loop run
#  currentnum = 4-1 = 3,
#  currentnum = 3-2 = 2
#  print( 3, 2 )
#  start = stop (start = 4)
#  stop += 3 (stro = 4+3 = 7)
#  currentnum = 7
**PROBLEM** 
# for row in range(7, 6):    
# for col in range(4, 7): 5,6,7 means 3 time will loop run
#  currentnum = 7-1 = 6,
#  currentnum = 7-2 = 5,
#  currentnum = 7-3 = 4,
#  print( 6, 5, 4)
#  start = stop (start = 7)
#  stop += 3 (stro = 7+3 = 11)
#  currentnum = 11

问题(talking from the #commented calculations):

for i in range(11, 6):
for j in range(4, 7):
print("h")
print("k")
print("j")

这个For循环将不会执行，因为(11,6)。

这就是我的计算出错的地方，我知道我再没有线索这个解决方案是如何工作的。如果有人对当前的解决方案有更好的解决方案或解释，我们将不胜感激。

只是想知道代码是如何工作的

谢谢。

Answer 1

我认为你理解的问题是每次停止改变时重写第一个for循环。但是，不应该这样做，因为for循环只在开始时进行计算，因此更改变量stop在循环已经运行时不应该对循环产生影响，如果这样做有意义的话。我更正了你的"理解"部分:

#### for loop does not change
# for row in range(2, 6): 2, 3, 4, 5,
### for loop 2 ###
#     for col in range(1, 2):
#         currentNumber -= 1  # 2-1 = 1
#         print(1)
#      start = stop  # (start = 2)
#      stop += 2  # (row currently = 2) so now stop = 2 + 2 = 4
#      currentNumber = 4
### for loop 3 ###
#     for col in range(2, 4): 2, 3 means 2 time will loop run
#         currentnum = 4-1 = 3,
#         currentnum = 3-2 = 2
#         print(3, 2)
#     start = stop  # (start = 4)
#     stop += 3  # (row currently = 3) so now stop = 4 + 3 = 7
#     currentnum = 7
### for loop 4 ###
#     for col in range(4, 7):  # 4, 5, 6 i.e. loop 3 times
#         currentnum = 7-1 = 6,
#         currentnum = 6-1 = 5
#         currentnum = 5 - 1 = 4
#         print(6, 5, 4)
#     start = stop  # (start = 7)
#     stop += 4  # (row currently = 4) so now stop = 7 + 4 = 11
#     currentnum = 11
### for loop 5 ###
#     for col in range(7, 11):  # 7, 8, 9, 10 i.e. loop 4 times
#         currentnum = 11 - 1 = 10
#         currentnum = 10 - 1 = 9
#         currentnum = 9 - 1 = 8
#         currentnum = 8 - 1 = 7
#         print(10, 9, 8, 7)
#     start = stop  # (start = 11)
#     stop += 5  # (row currently = 5) so now stop = 11 + 5 = 16
#     currentnum = 16

希望这是有意义的，但请随时要求澄清。注意，最后几行并不重要，因为它是最后一个for循环。