GraphQL Flutter中的Http标头



我正在使用GraphQL。我需要将参数传递给Http标头。然而,我看到了一个只传递普通参数的选项(下面的代码)。请告诉我怎么做!!

Query(
options: QueryOptions(
document: gql(userGraphQL),
variables: {
"..." : "..."
}
),
builder: ...
)

我创建了这个文件来关联GraphQL

gql_utils.dartfile

class GraphQLUtils {
static final GraphQLUtils _instance = GraphQLUtils._internal();
GraphQLClient? _client;
factory GraphQLUtils() {
return _instance;
}
GraphQLUtils._internal() {
final httpLink = HttpLink(
'your base url',
);
final authLink = AuthLink(
ignore: undefined_identifier
getToken: () async => 'Bearer $YOUR_PERSONAL_ACCESS_TOKEN',
);
var link = authLink.concat(httpLink);
var link = httpLink;
var link = httpLink;
final policies = Policies(
fetch: FetchPolicy.networkOnly,
);
_client = GraphQLClient(
cache: GraphQLCache(),
link: link,
defaultPolicies: DefaultPolicies(
watchQuery: policies,
query: policies,
mutate: policies,
),
);
}
Future<Map<String, dynamic>> queryRepo(
DocumentNode readRepositories, map) async {
final options = WatchQueryOptions(
document: readRepositories,
variables: map,
pollInterval: const Duration(seconds: 4),
fetchResults: true,
);
QueryResult result = await _client!.query(options);
if (result.hasException) {
Map<String, dynamic> response = <String, dynamic>{};
response['success'] = false;
response['message'] = result.exception!.graphqlErrors[0].message;
return response;
} else {
Map<String, dynamic> response = <String, dynamic>{};
response['success'] = true;
response['data'] = result.data;
return response;
}
}
}

这是一个示例查询类

class UserQueries {
static final userInsertQuery = gql(r'''
mutation Insert_users($objects: [users_insert_input!]!, $onConflict: users_on_conflict) {
insert_users(objects: $objects, on_conflict: $onConflict) {
returning {
id
name
timestamp
}
}
}
''');
}

和如何调用api

Future insertUserApi(String name) async {
try {
Map<String, dynamic> variables = <String, dynamic>{};
variables = {
"objects": [
{"name": name}
],
"onConflict": {
"constraint": "users_pkey",
"update_columns": [
"id",
"name",
]
}
};
await GraphQLUtils()
.queryRepo(UserQueries.userInsertQuery, variables)
.then((response) async {
if (response["data"] != null) {
print("----Data---:${response["data"]}");
Get.back();
} else {
Get.snackbar(
"Error",
"Something Went wrong",
);
}
});
} catch (e, st) {
Get.snackbar(
"Error",
e.toString(),
);
}
}