如何根据用户输入从列表中返回元素

Question

我应该创建一个以列表和标题为字符串的函数，然后从基于标题的列表。

def find_appointment(lst, title = ""):
if title in lst:
funn = lst.find(title)
return funn
else:
print("No result")
appointments = ["Zoo: 11.03.22", "Shopping: 13.08.22", "Christmas: 24.12.22", "Funeral: 25.12.22"]
find_appointment(appointments, "Zoo")

我希望得到"；动物园：11.03.22〃；，而是得到了"；没有结果"；

这里的清单只是我随便编的。在实际列表中，我不知道项目。

Answer 1

这是我的解决方案：

def find_appointment(lst, title = ""):
for i in lst:
if title in i:
return index
else:
print("No result")
appointments = ["Zoo: 11.03.22", "Shopping: 13.08.22", "Christmas: 24.12.22", "Funeral: 25.12.22"]
print(find_appointment(appointments, "Zoo"))

Answer 2

您需要使用的是字典。就像：

appointments = {"Zoo":"11.03.22", "Shopping": "13.08.22"}
something_to_find = "Zoo"

然后在字典里找到一些东西：

def find_something(lst, title=" "):
print(lst[title])
find_something(appointments,something_to_find)

所以，是的，你可能想读字典。W3schools是一个很好的起点[https://www.w3schools.com/python/python_dictionaries.asp]

Answer 3

def find_appointment(lst, title = ""):
for i in lst:
if title in i:
a=title.find(title)
return a
else:
print("No result")
appointments = ["Zoo: 11.03.22", "Shopping: 13.08.22", "Christmas: 24.12.22", 
"Funeral: 25.12.22"] 
print(find_appointment(appointments, "Zoo"))
#hope this helps. in order to iterate through all elements in list. we have to 
use a loop. once the value is found we can get its index by find method of 
string.