我没有用python完成一个程序，两天后我回来发现了这个。有人知道这是怎么发生的吗？我在Sublime Text 中编码
matrix.append(int(a[count_a]))
matrix.append(int(vectors[j][i]))
print(a[count_a], end="")
print(vectors[j][i], end="")
count_a2 += 1
count_first = False
else:
if count_a2 == count_tringle:
out_A.append("("+i+")")
out_A.append(i)
out_Ael.append("("+i+")")
out_Ael.append(i)
print("+"+vectors[j][i]+"λ"+str(count_alfa), end="")
print(vectors[j][i]+"λ "+str(count_alfa), end="")
# entering into the vectors dictionary
A_str.append(str(i))
None
count_a += 1
count_alfa += 1
else:
else:
else:
first = False
for j in keys_list:
i = str(i)
if int(i) < 0:
if int(i) < 0:
if int(vectors[j][i]) > 0 and count_first is False:
matrix.append(int(vectors[j][i]))
opred_matrix_3x3(matrix)
print(" ", j, end=")
print("= ", end="")
print("|", end="")
print("The matrix is not 3x3, find the determinant yourself")
print("For example: p 3 -2 4n "+""*10+"g -2 1 3n "+""*10+"r 7 -4 1 (in three dimensions)")
print("Wrong number of characters! Print againn")
print()
print()
print(vectors[j][i], end=")
vectors[j[0]] = j[1:]
x -= 1
# input
# output all
# checks
# intermediate things
# let's make the negative intermediate things put in parentheses too
# let's put negative numbers in brackets
A_el1 = A[0]*A[4]*A[8]
A_el2 = A[1]*A[5]*A[6]
A_el3 = A[3]*A[2]*A[7]
A_el4 = A[6]*A[4]*A[2]
A_el5 = A[1]*A[3]*A[8]
A_el6 = A[0]*A[5]*A[7]
A_str=[]
Ael = [A_el1, A_el2, A_el3, A_el4, A_el5, A_el6]
count_a += 1
count_alfa = 1
count_first = True
count_tringle += 1
elif 0 == 1:
else:
else:
for i in A:
for i in A_str:
for i in Ael:
for i in x:
for j in keys_list:
for j in keys_list:
for j in vectors[i]:
global opred_A, out_A
if dim == 3:
if first:
if len(j) != dim+1:
j = input("")
j = j.split()
matrix = []
opred_A = (A[0]*A[4]*A[8]+A[1]*A[5]*A[6]+A[3]*A[2]*A[7]-A[6]*A[4]*A[2]-A[1]*A[3]*A[8]-A[0]*A[5]*A[7])
opred_matrix_3x3(matrix)
out_A = []
out_Ael = []
print(" ", i, end="")
print(" =",a[count_a])
print(")")
print("= ", end="")
print("{}{}*{}*{} + {}*{}*{} + {}*{}*{} - {}*{}*{} - {}*{}*{} - {}*{}*{} =". format(out_A[0], out_A[4], out_A[8], out_A[1], out_A[5], out_A[6], out_A[3], out_A[2], out_A[7], out_A[6], out_A[4], out_A[2], out_A[1], out_A[3], out_A[8], out_A[0], out_A[5], out_A[7]), end= ")
print("{}+{}+{}-{}-{}-{} = {}n".format(out_Ael[0], out_Ael[1], out_Ael[2], out_Ael[3], out_Ael[4], out_Ael[5], opred_A))
print("|")
print("|", end="")
print("Δ "+str(count_tringle))
print("Enter the name of the basis vector and its values with spaces")
print("The matrix is not 3x3, find the determinant yourself")
print("⃗"+str(i),"= (",end=")
print()
return (A[0]*A[4]*A[8]+A[1]*A[5]*A[6]+A[3]*A[2]*A[7]-A[6]*A[4]*A[2]-A[1]*A[3]*A[8]-A[0]*A[5]*A[7])
# ------------ENTRY------------
# ------------Estage 1------------
# ------------Stage 2------------
# ------------Step 3------------
# dim - dimentional
# Entry
# just a triangle
# triangles with numbers
a = a.split()
a = input("By analogy, enter the data of the decomposable vectorfor example: a 25 -15 14n")
count_a = 0
count_a = 1
count_a2 = 1
count_alfa = 1
count_tringle = 1
def opred(A):
def opred_matrix_3x3(A):
dim = int(input("How many dimensions?n"))
else:
first = True
for i in a[1:]:
for i in keys_list:
for i in x:
for i in x:
if dim == 3:
input()
keys_list = list(vectors.keys())
matrix = []
print("(number after λ - index λ)")
print(")n")
print("1)given")
print("nThe delta triangles")
print("Δ")
print("⃗"+a[0],"= (",end=")
vectors = {} # dictionary of all vectors
while count_tringle <= dim:
while x>0:
x = len(range(1,dim+1))
x = list(range(0,dim))
对不起我的蟒蛇
对于stackoverflow：x x x x
哦。。。也许我不小心按了CTRL+A和f9…