如何从字符串中筛选准确的单词

Question

我的主要目标是检查字符串是否包含单词数组。如果字符串在单词前面包含$，我不希望它检查字符串中的单词数组，并希望直接console.log它。

我遇到的问题是它没有检查"；精确的单词"；。例如，如果你放E，文本应该显示出来，因为没有只包含"E"的单词，但它没有显示出来。

例如：

const res = `EU, U.S. REACH DEAL TO RESOLVE BOEING-AIRBUS TRADE DISPUTE
$BA`;
const filters = ["E", "OPEC", "Repo"];
if (!filters.some(element => res.includes(element))) {
console.log(res);
}

另一种方法，我想也许可以使用split方法来检查每个数组项，无论它是否是过滤单词。

Answer 1

var res = `EU, U.S. REACH DEAL TO RESOLVE BOEING-AIRBUS TRADE DISPUTE $BA`;
var filters = ["E", "OPEC", "Repo"];
if (filters.some(element => new RegExp('\b'+element + '\b').test(res))) {
console.log(res);
}

Answer 2

使用带有表达式体的ES6 Array.filter((和箭头函数：

var words = ['get', 'help', 'set', 'moon', 'class', 'code', 'Get',  ];
var letter = 'e';
var word = "get";
const output = words.filter(x=>x.includes(letter));
console.log(output);
const output2 = words.filter(x => x.toLowerCase().includes(word));
console.log(output2);

Answer 3

.split()将每个字符串放入一个小写字符串数组中(分隔符是空格或逗号(。如果要过滤的字符串不止一个，请将它们放入数组中

const strings = ['aaa, BBB, ccc', 'vhko nuu', 'String'];
let arrArr = strings.map(str => {
return str.toLowerCase().split(/[,s]/);
});
// arrArr = [['aaa', 'bbb', 'ccc'], ['vhko', 'nuu'], ['string']]

然后通过.flatMap((strArr, idx)...运行arrArr(数组(的每个字符串数组，通过.flatMap(str...运行strArr(字符串数组(的各个字符串

return arrArr.flatMap((strArr, idx) => {
return strArr.flatMap(str => {...

对于每个str(字符串(，在三进制中使用.includes(list)和.startsWith(char)来测试>str是否在列表中，或者它是否以特定字符串开始(如果传递了第三个参数char[/em>(。

<IF> list.includes(str) ? <TRUE|THEN> [strings[idx]] 
: <ELSE IF> char && str.startsWith(char) ? <TRUE|THEN> [strings[idx]] 
: <ELSE|THEN> []; 

const strs = [
`EU, U.S. REACH DEAL TO RESOLVE BOEING-AIRBUS TRADE DISPUTE $BA`, 
`a, b, C, d, E, f`, 
`OPEC reaches agreement`, 
`This has opec., repo#, and a dollar$ so this should be ignored`
];
const words = ["e", "opec", "repo"];
const wordFilter = (list, strings, char) => {
let arrArr = strings.map(str => {
return str.toLowerCase().split(/[,s]/);
});
return arrArr.flatMap((strArr, idx) => {
return strArr.flatMap(str => {
return list.includes(str) ? [strings[idx]] : 
char && str.startsWith(char) ? [strings[idx]] : 
[];
});
});
};
console.log(wordFilter(words, strs, '$'));

Answer 4

我想你可以从这个例子中得到一些想法。点击此处查看jsFiddle

var words = ['get', 'help', 'set', 'moon', 'class', 'code'];
var letter = 'e';
function find(words, letter) {
letter = letter.split(''); //get it to as  object the  we can use it in every method as follwing
return words.filter(function(word) { //get pne buy one word in words array
return letter.every(function(char) {
return word.includes(char); // return word including the letter that you request
});
});
}
const output = find(words, letter);
console.log(output);