如何使用python请求使用graphql上传文件

Question

我有一个通过失眠生成的curl代码，它运行良好。我只是想不出用python请求来复制它。

curl --request POST 
--url MY_SERVER_URL 
--header 'Accept: application/json' 
--header 'Content-type: multipart/form-data; boundary=---011000010111000001101001' 
--header 'Authorization:  AUTH_TOKEN' 
--form 'operations={
"query": "mutation($file: Upload!, $path: String!, $private: Boolean) { uploadFile(file: $file, path: $path, private: $private) }",
"variables": {
"file": null,
"path": "test",
"private": false
}
}' 
--form 'map={ "0": ["variables.file"] }' 
--form '0=@E:DevelopmentTechnologyPythonsmall_utilitiesbarwisrandom-filesfilescsvsabove serious.csv'

感谢

Answer 1

我找到了解决方案。若有人有相同的问题，这里是参考代码。

file = open('FILE_PATH', 'rb')
auth_headers = {
"Authorization": f"Bearer {token}"
}
query = """
mutation($file: Upload!, $path: String!, $private: Boolean) { 
uploadFile(file: $file, path: $path, private: $private) 
}
"""

variables = { 
"file": None,
"path": 'test',
"private": True
}  
operations = json.dumps({
"query": query,
"variables": variables
})
map = json.dumps({ "0": ["variables.file"] })

response = requests.post(graphql_url, data = {
"operations": operations,
"map": map
},
files = {
"0" : file
},
headers = auth_headers
)

Answer 2

另一个选项是使用graphql-python/gql库。它支持上传文件，即使是流媒体！

transport = AIOHTTPTransport(url='YOUR_URL')
# Or transport = RequestsHTTPTransport(url='YOUR_URL')
client = Client(transport=transport)
query = gql('''
mutation($file: Upload!) {
singleUpload(file: $file) {
id
}
}
''')
with open("YOUR_FILE_PATH", "rb") as f:
params = {"file": f}
result = client.execute(
query, variable_values=params, upload_files=True
)