如何获得children属性+ parent元素

Question

我想写一个SQL Server存储过程来解析XML数据以检索值:

DECLARE @Champs TABLE 
(
NU_LINE VARCHAR(4), 
"KEY" VARCHAR(200), 
LABEL VARCHAR(200), 
API_NAME VARCHAR(200), 
API_FIELD VARCHAR(200), 
"VALUE" VARCHAR(MAX)
);  
DECLARE @docHandle int;  
DECLARE @xmlDocument nvarchar(max); -- or xml type  
SET @xmlDocument = N'<STRUCTURE>
<GRILLE>
<ROWS>
<ROW>
<NU_LINE>1</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="ABC123" />
<CHAMP KEY="RES" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="JAMES" />
<CHAMP KEY="DATE_BEGIN" API_NAME="CCC" API_FIELD="BBB" VALUE="14/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="CCC" API_FIELD="BBB" VALUE="28/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>2</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="ABC" API_NAME="DDD" API_FIELD="EEE" VALUE="CDE345" />
<CHAMP KEY="DATE_RES" LABEL="CDE" API_NAME="DDD" API_FIELD="EEE" VALUE="06/05/2021" />
<CHAMP KEY="RES" LABEL="DEF" API_NAME="DDD" API_FIELD="EEE" VALUE="JOHN" />
<CHAMP KEY="DATE_BEGIN" API_NAME="DDD" API_FIELD="EEE" VALUE="07/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="DDD" API_FIELD="EEE" VALUE="14/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>3</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="EFG567" />
<CHAMP KEY="DATE_RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="10/05/2021" />
<CHAMP KEY="RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="JIM" />
<CHAMP KEY="DATE_BEGIN" API_NAME="FFF" API_FIELD="GGG" VALUE="24/07/2021" />
<CHAMP KEY="DATE_END" API_NAME="FFF" API_FIELD="GGG" VALUE="31/07/2021" />
</CHAMPS>
</ROW>
</ROWS>
</GRILLE>
</STRUCTURE>'
EXEC sp_xml_preparedocument @docHandle OUTPUT, @xmlDocument;  
-- Use OPENXML to provide rowset consisting of customer data.  
INSERT @Champs   
SELECT *   
FROM OPENXML(@docHandle, N'/STRUCTURE/GRILLE/ROWS/ROW/CHAMPS/CHAMP') 
WITH (NU_LINE VARCHAR(4), "KEY" VARCHAR(200), LABEL VARCHAR(200), API_NAME VARCHAR(200), API_FIELD VARCHAR(200), "VALUE" VARCHAR(MAX))
SELECT * FROM @Champs

但在我的结果NU_LIGNE总是空的。

如何为每一行分别获得NU_LINE 1, 2或3 ?

提前谢谢你。

Answer 1

正如我在评论中提到的，不要使用那些旧的过程;它们是为了兼容SQL Server2000。SQL Server从2005年起就支持XQUERY了，所以你没有理由在16年后不使用它。如果你这样做了，这就简单多了:

DECLARE @xmlDocument  xml; 
SET @xmlDocument = N'<STRUCTURE>
<GRILLE>
<ROWS>
<ROW>
<NU_LINE>1</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="ABC123" />
<CHAMP KEY="RES" LABEL="AAA" API_NAME="AAA" API_FIELD="BBB" VALUE="JAMES" />
<CHAMP KEY="DATE_BEGIN" API_NAME="CCC" API_FIELD="BBB" VALUE="14/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="CCC" API_FIELD="BBB" VALUE="28/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>2</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="ABC" API_NAME="DDD" API_FIELD="EEE" VALUE="CDE345" />
<CHAMP KEY="DATE_RES" LABEL="CDE" API_NAME="DDD" API_FIELD="EEE" VALUE="06/05/2021" />
<CHAMP KEY="RES" LABEL="DEF" API_NAME="DDD" API_FIELD="EEE" VALUE="JOHN" />
<CHAMP KEY="DATE_BEGIN" API_NAME="DDD" API_FIELD="EEE" VALUE="07/08/2021" />
<CHAMP KEY="DATE_END" API_NAME="DDD" API_FIELD="EEE" VALUE="14/08/2021" />
</CHAMPS>
</ROW>
<ROW>
<NU_LINE>3</NU_LINE>
<CHAMPS>
<CHAMP KEY="NUMBER" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="EFG567" />
<CHAMP KEY="DATE_RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="10/05/2021" />
<CHAMP KEY="RES" LABEL="OOO" API_NAME="FFF" API_FIELD="GGG" VALUE="JIM" />
<CHAMP KEY="DATE_BEGIN" API_NAME="FFF" API_FIELD="GGG" VALUE="24/07/2021" />
<CHAMP KEY="DATE_END" API_NAME="FFF" API_FIELD="GGG" VALUE="31/07/2021" />
</CHAMPS>
</ROW>
</ROWS>
</GRILLE>
</STRUCTURE>';
SELECT R.R.value('(NU_LINE/text())[1]','int') AS NU_LINE,
C.C.value('@KEY','varchar(200)') AS [KEY],
C.C.value('@LABEL','varchar(200)') AS [LABEL],
C.C.value('@API_NAME','varchar(200)') AS [API_NAME],
C.C.value('@API_FIELD','varchar(200)') AS [API_FIELD],
C.C.value('@VALUE','varchar(MAX)') AS [VALUE]
FROM @xmlDocument.nodes('/STRUCTURE/GRILLE/ROWS/ROW')R(R)
CROSS APPLY R.R.nodes('CHAMPS/CHAMP')C(C);

,db&lt的在小提琴