我希望根据该值以下最接近的匹配连接到一个值。在SQL中,我可以很容易地做到这一点。考虑以下数据:
tblActuals
|Date |Temperature:
|09/02/2020 |14.1
|10/02/2020 |15.3
|11/02/2020 |12.2
|12/02/2020 |12.4
|13/02/2020 |12.5
|14/02/2020 |11
|15/02/2020 |14.6
tblCoefficients:
|Metric |Coefficient
|10.5 |0.997825593
|11 |0.997825593
|11.5 |0.997663198
|12 |0.997307614
|12.5 |0.996848773
|13 |0.996468537
|13.5 |0.99638519
|14 |0.996726301
|14.5 |0.997435894
|15 |0.998311153
|15.5 |0.999135509
在SQL中,我可以使用下面的命令来实现连接:
Select
a.date,
b.temperature,
(select top 1 b.Coefficient from tblCoefficients b where b.Metric <= a.Temperature order by b.Metric desc) as coefficient
from tblActuals
是否有任何方法可以在两个pyspark数据框架中实现与上述相同的数据?我可以在spark SQL中实现类似的结果,但我需要数据框架的灵活性,用于我在数据库块中创建的过程。
您可以执行连接并获得最大(最接近)度量的系数:
import pyspark.sql.functions as F
result = tblActuals.join(
tblCoefficients,
tblActuals['Temperature'] >= tblCoefficients['Metric']
).groupBy(tblActuals.columns).agg(
F.max(F.struct('Metric', 'Coefficient'))['Coefficient'].alias('coefficient')
)
result.show()
+----------+-----------+-----------+
| Date|Temperature|coefficient|
+----------+-----------+-----------+
|15/02/2020| 14.6|0.997435894|
|12/02/2020| 12.4|0.997307614|
|14/02/2020| 11.0|0.997825593|
|13/02/2020| 12.5|0.996848773|
|11/02/2020| 12.2|0.997307614|
|10/02/2020| 15.3|0.998311153|
|09/02/2020| 14.1|0.996726301|
+----------+-----------+-----------+