while循环中的计数器不能正常工作

Question

我正在做一个原始数字猜谜游戏。下面是我的代码:

number = 68
counter=0
limit=3
guess = input("Guess the number from 1 to 100:")
while counter < limit:
if int(guess) != number:
counter+=1
if int(guess) < number:
guess = input("Too low, try again:")
if int(guess) > number: 
guess = input("Too high, try again:")
if int(guess) == number:
print("You won!")
break 

它一直要求我输入超过3次，并且程序不会停止工作，直到我输入较低的数字3次，反之亦然。怎么解呢?

Answer 1

if int(guess) < number:
guess = input("Too low, try again:")
if int(guess) > number: 
guess = input("Too high, try again:")

这是有问题的，因为您接受输入，然后重新检查新的输入/数字。这应该是if/else语句。

Answer 2

number = 68
counter=0
limit=3
guess = input("Guess the number from 1 to 100: ")
while counter < limit:
if int(guess) != number:
counter += 1
if int(guess) < number:
guess = input("Too low, try again:")
else:
guess = input("Too high, try again:")
if int(guess) == number:
print("You won!")
break

可以看到，if语句已经变成了else语句。

Answer 3

你必须用"elif"命令。在第一个if部分中，您取2个预测并增加计数器1次。

Answer 4

正如之前提到的问题是你的if条件，但我会进一步优化它:

number = 68

counter = 0

limit = 3

input_message = "Guess the number from 1 to 100: "
final_message = "You lost"


while counter < limit:
guess = int(input(input_message))
if guess == number:
final_message = "You won!"

break
    
if guess < number:
input_message = "Too low. Try again: "

else:
input_message = "Too high. Try again: "
    
counter += 1

print(final_message)