我的气泡排序类出错，类中有什么问题？

Question

我正在学习python，昨天开始冒泡排序，但我似乎找不到错误，我一直在试图找到错误，但我没有足够的知识来找到它。如果有人能给我指路就太好了:

class BubbleSort1:
def __init__(self) -> None:
pass
def read(self):
lst = None
lst = []
n1 = int(input('Enter the number of values to be sorted:'))
print('Enter the values to be sorted')
for i in range(0,n1):
ele = int(input())
lst.append(ele)
print('Unsorted list:')
print(lst)
def sort(self,lst):
for i in range(len(lst)-1,0,-1):
for j in range(i):
if lst[j] > lst[j+1]:
temp = lst[j]
lst[j] = lst[j+1]
lst[j+1] = temp
def display(self,lst):
print('sorted list')
print(len(lst))
object1 = BubbleSort1()
object1.read()
object1.sort()
object1.display()

错误是

> Enter the number of values to be sorted:5
>     Enter the values to be sorted
>     5
>     4
>     3
>     2
>     1
>     Unsorted list:
>     [5, 4, 3, 2, 1]
>     Traceback (most recent call last):
>       File "c:UsersUser1OneDriveDesktopNew foldercopy", line 31, in <module>
>         object1.sort()
>     TypeError: BubbleSort1.sort() missing 1 required positional argument: 'lst'

Answer 1

您有两个选择:

1. 从read返回lst，将lst传递给sort,display
2. 设置lst为self.lst，并在self的所有功能上使用该lst。

Option_1您不将lst传递给sort()和display()。你可以通过从read返回lst并传递给sort()和display()来解决这个问题。

class BubbleSort1:
def __init__(self) -> None:
pass
def read(self):
lst = []
n1 = int(input('Enter the number of values to be sorted:'))
print('Enter the values to be sorted')
for i in range(0,n1):
ele = int(input())
lst.append(ele)
print('Unsorted list:')
print(lst)
return lst
def sort(self,lst):
for i in range(len(lst)-1,0,-1):
for j in range(i):
if lst[j] > lst[j+1]:
temp = lst[j]
lst[j] = lst[j+1]
lst[j+1] = temp

def display(self,lst):
print('sorted list')
print(lst)
object1 = BubbleSort1()
lst = object1.read()
object1.sort(lst)
object1.display(lst)

Option_2

class BubbleSort1:
def __init__(self) -> None:
self.lst = []
def read(self):
lst = []
n1 = int(input('Enter the number of values to be sorted:'))
print('Enter the values to be sorted')
for i in range(0,n1):
ele = int(input())
lst.append(ele)
print('Unsorted list:')
print(lst)
self.lst = lst
def sort(self):
lst = self.lst
for i in range(len(lst)-1,0,-1):
for j in range(i):
if lst[j] > lst[j+1]:
temp = lst[j]
lst[j] = lst[j+1]
lst[j+1] = temp

def display(self):
print('sorted list')
print(self.lst)


object1 = BubbleSort1()
object1.read()
object1.sort()
object1.display()

输出:

Enter the number of values to be sorted:3
Enter the values to be sorted
1
3
2
Unsorted list:
[1, 3, 2]
sorted list
[1, 2, 3]