Python请求未返回完整的HTML源代码



我正在尝试检索完整的HTML源代码,但我发现它只返回部分。

代码:

from bs4 import BeautifulSoup as soup
import requests 
HEADERS ={'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.76 Safari/537.36', "Upgrade-Insecure-Requests": "1","DNT": "1","Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8","Accept-Language": "en-US,en;q=0.5","Accept-Encoding": "gzip, deflate"}
url = 'https://us.louisvuitton.com/eng-us/products/louis-vuitton-and-nike-air-force-1-by-virgil-abloh-white-white-white-nvprod3690049v/1A9V88'
req = requests.get(url, headers=HEADERS)
page_soup = soup(req.text, "html5lib")
print(page_soup)

如果你浏览网站及其源代码,你会发现它有181行长。但在代码中,它返回45行长。

知道我做错了什么吗?非常感谢。

尝试执行page_soup.getText()以从beautifulSoup对象中获取整个文本