我如何通过运行命令行参数从Maven和Surefire插件作为属性在pom.xml?

Question

如何将参数从命令行传递到pom.xml文件中的属性?

我有以下pom文件

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>BusniessApp</groupId>
<artifactId>Test-Automation</artifactId>
<version>1.0-SNAPSHOT</version>
<properties>
<maven.compiler.source>8</maven.compiler.source>
<maven.compiler.target>8</maven.compiler.target>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<build>
<plugins>
[...]
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<version>3.0.0</version>
<configuration>
<suiteXmlFiles>
<suiteXmlFile>testng.xml</suiteXmlFile>
</suiteXmlFiles>
<properties>
<property>
<name>testnames</name>
<value>Android,iOS</value>
</property>
</properties>
[...........]
</build>
<dependencies>
[...]
</dependencies>
</project>

我累了mvn clean test -Dtestnames=iOS，如传递命令行参数从Maven作为属性在pom.xml中所述，但它仍然运行在pom.xml

中设置的默认值

Answer 1

找到了解决方案，至少一个适合我的。我必须在POM中创建一个属性，然后将其传递给构建部分。结果是这样的

<properties>
<maven.compiler.release>11</maven.compiler.release>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<myArgument>DefaultValue</myArgument>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.8.0</version>
<configuration>
<release>11</release>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<version>3.0.0</version>
<configuration>
<suiteXmlFiles>
<suiteXmlFile>testng.xml</suiteXmlFile>
</suiteXmlFiles>
<properties>
<testnames>${myArgument}</testnames>
</properties>
</configuration>
</plugin>
</plugins>
</build>