类型错误：__init__() 缺少 1 个必需的位置参数：从命令行调用时'message'

Question

我正在努力从命令行传递一些参数，到目前为止，代码看起来像这样:

class DeviceManager:
def __init__(self):
self.network_ip = self.__get_network_ip__()
self.devices = self.__get_devices__()
self.sort_by("id")
...other methods such as pick_by_rangeID(f,t)...

文件Tool.py:

import argparse
from Device_Manager import*
if __name__ == "__main__":
dm = DeviceManager()
parser = argparse.ArgumentParser()

parser.add_argument("method", help ="method to call")
parser.add_argument("-f", type = int, help ="from")
parser.add_argument("-t", type = int, help ="to")
args = parser.parse_args()

if args.method == "sbID":
dm.pick_by_range_ID(args.f,args.t)

我期望从命令行调用它为:python Tool.py sbID -f 5 -t 6，这导致我的错误:TypeError: __init__() missing 1 required positional argument: 'message'，据我所知，这发生在一个对象被初始化时，它的类缺少参数。令我惊讶的是，如果我像下面这样直接运行这个方法，异常不会发生。

dm = DeviceManager()
devs = dm.pick_by_range_ID(5,6)

我该如何解决这个问题?

编辑:添加pick_by_rangeID方法:

def pick_by_range_ID(self,from_ID = 0, to_ID = 999999) -> list:
selected = []
for dev in self.devices:
id = dev.deviceID
if id >= from_ID and id <= to_ID:
selected.append(dev)
if len(selected) == 0:
raise ArgumentError("There are no IDs in that range.")
return selected

Answer 1

解决方案:问题在这一行:

raise ArgumentError("There are no IDs in that range.")

ArgumentError接受两个参数(class) ArgumentError(argument: Action | None, message: str)

我是这样解决的:

raise ArgumentError(None, "There are no IDs in that range.")