如何将多个列表从一个变量变成一个列表(ooov11)?

Question

我有一个字段:

overtime_50 = fields.Char(readonly=True, default='00:00')

我对这个字段做了一个列表，我得到了这么多列表:

def _compute_sum_50(self):
for record in self:
x = [record.overtime_50]
print(x)

控制台打印:

['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']
['00:00']

我需要得到这样的东西:

['00:00','00:00','00:00','00:00','00:00','00:00','00:00','00:00','00:00']

我尝试了很多方法，但我只得到这样的结果:

def _compute_sum_50(self):
for record in self:
x = [record.overtime_50]
print(list(chain.from_iterable(x)))

控制台打印:

['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']
['0', '0', ':', '0', '0']

我能做错什么?

Answer 1

def _compute_sum_50(self):
x = [record.overtime_50for record in self] # Use List Comprehension
print(x)

编辑:Dipen Shah提供的更好解决方案