使用foreach修改JSON文件

Question

有一个json文件:

$json='[{"Email":"[e-mail]","Name":"company 1","Tel1":"xx-xx-xx","Adresse":"XXXXXX"},{"Email":"[e-mail]","Name":"Company 2","Tel1":"xx-xx-xx","Adresse":"XXXXXX"}]';

和我的表单在变量中发布数据和"var ="fname"=; Ameur","lname" =祝辞;"KHIL"fname"=祝辞;"Marak","lname" =祝辞;"Cristo"

我喜欢在json内容中插入变量得到最终的json，像这样:

$result='[{"Email":"[e-mail]","Name":"company 1","vars":{"fname":"Ameur","lname":"KHIL","Tel1":"xx-xx-xx","Adresse":"XXXXXX"}},{"Email":"[e-mail]","Name":"Company 2","vars":{"fname":"Marak","lname":"Cristo","Tel1":"xx-xx-xx","Adresse":"XXXXXX"}}]';

Answer 1

为此，您可以使用json_decode()将JSON-String解析为PHP-Object。然后，您只需将新值vars设置为给定的表单值。

解析JSON-String

$json = json_decode('[{"Email":"[e-mail]","Name":"company 1","Tel1":"xx-xx-xx","Adresse":"XXXXXX"},{"Email":"[e-mail]","Name":"Company 2","Tel1":"xx-xx-xx","Adresse":"XXXXXX"}]');

添加新的变量值并删除额外的变量值。这只是针对第一个条目，其他条目也可以这样做，甚至可以对多个条目进行迭代

$json[0]->vars = ["fname" => "Marak", "lname" => "Cristo", "Tel1" => $json[0]->Tel1,"Adresse" => $json[0]->Adresse];
unset($json[0]->Tel1);
unset($json[0]->Adresse);

并在JSON-String

中获得结果

$result = json_encode($json);