如何删除json中的对象

Question

"Admins": [
{
"Admin_name": "admin",
"Admin_pass": "admin"
},
{
"Admin_name": "administrator",
"Admin_pass": "password"
}
],
"Teachers": [
{
"Name": "Yersin Zhanabekov",
"Course": "Physical Culture",
"Login": "Yersin.Zhanabekov",
"Pass": "Yersin123",
"Mark": null
},
{
"Name": "Kayrat Mynbayev",
"Course": "Theory of Probability and Mathematical Statistics",
"Login": "Kayrat.Mynbayev",
"Pass": "Kayrat123",
"Mark": null
},
{
"Name": "Magzhan Ikram",
"Course": "Python",
"Login": "Magzhan .Ikram",
"Pass": "Magzhan123",
"Mark": null
},
{
"Name": "Mag",
"Course": "Python",
"Login": "Magzhan .Ikram",
"Pass": "Magzhan123",
"Mark": null
}
], },
{
"Name": "Mag",
"Course": "Python",
"Login": "Magzhan",
"Pass": "Magzhan123",
"Mark": null
}
],

with open('dict.json', 'r') as rf:
dataRead = json.load(rf)

log = input("Your username: ")
pas = input("Your password: ")
for name in dataRead['Admins']:
if log == name['Admin_name'] and pas == name['Admin_pass']:
y = {'Name': "Hello"}
dataRead['Teachers'][3]['Name'].pop()
dataRead['Teachers'][3]['Name'].append(y)
with open('dict.json', 'w') as rf:
dataRead = json.dump(dataRead,rf)

我想删除对象名称，并将其更改为新的名称。有pop()或.delete()

但无论如何，我得到了相同的错误

我该怎么办?

错误是:

Traceback (most recent call last):
dataRead ['Teachers'] [3] ['Name']. pop () AttributeError: 'str' object has no attribute 'pop'

Answer 1

你应该这样做

dataRead['Teachers'][3]['Name'] = "Hello"

Answer 2

dataRead['Teachers']是一个列表。一旦你确定了列表中你想要删除的条目的索引(例如，3)，那么dataRead(['Teachers'].pop(3)

Answer 3

您还可以查看JSONPath表达式(使用jsonpath-ng等库)。它为您在JSON对象中导航提供了更大的灵活性。下面是一些例子:

改变特定元素的Name:

from jsonpath_ng.ext import parser
for match in parser.parse("$.Teachers[?(@.Name=='Mag')]").find(x):
match.value['Name'] = 'New'

从具有Name属性的元素中弹出Name:

for match in parser.parse("$.Teachers[?(@.Name)].[*]").find(x):
match.value.pop('Name')

为Teachers中的所有节点设置Name

for match in parser.parse("$.Teachers.[*]").find(x):
match.value['Name'] = 'New name'