swift解码json数据

Question

我有以下json数据返回从php。

{"Response":"OK","Data":[{"id":"1","organization_name":"Organization","description":"Description","address":"Address1, Ny, USA"}]}

需要使用swift解码

下面是我的代码。

struct OrgData: Decodable {
let data: [Data]
enum CodingKeys : String, CodingKey {
case data = "Data"
}
}
struct Data: Decodable {
let id: String
let address: String
let description: String
let organization_name: String

}

，我用

解码它

let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else {
print(error?.localizedDescription ?? "No data")
return
}
guard let dataObj = try? JSONDecoder().decode(OrgData.self, from: data) else {
print("Error: Couldn't decode data ")
return
}
..................

但dataObj中没有数据。

我指的是这篇文章

https://roadfiresoftware.com/2018/02/how-to-parse-json-with-swift-4/

Answer 1

你的结构是如何配置的一些问题:

• 没有对应"响应"的字段。值
• Data是一个数组，不是String

下面的代码可以正确输出你输入的json:

import Foundation
let json =
"""
{"Response":"OK","Data":[{"id":"1","organization_name":"Organization","description":"Description","address":"Address1, Ny, USA"}]}
"""
// MARK: - OrgData
struct OrgData: Codable {
let response: String
let data: [Datum]
enum CodingKeys: String, CodingKey {
case response = "Response"
case data = "Data"
}
}
// MARK: - Datum
struct Datum: Codable {
let id, organizationName, datumDescription, address: String
enum CodingKeys: String, CodingKey {
case id
case organizationName = "organization_name"
case datumDescription = "description"
case address
}
}
guard let data = json.data(using: .utf8) else {
return
}
do {
let dataObj = try JSONDecoder().decode(OrgData.self,
from: data)
print(dataObj)
// Optional(__lldb_expr_1.OrgData(response: "OK", data: [__lldb_expr_1.Datum(id: "1", organizationName: "Organization", datumDescription: "Description", address: "Address1, Ny, USA")]))
} catch {
print(error)
}

Answer 2

在helper类中创建一个函数

func decodedObject<T: Decodable>(_ type: T.Type, dictionaryData: JSONDictionary) throws -> T? {
guard let jsonData = try? JSONSerialization.data(withJSONObject: dictionaryData,
options: JSONSerialization.WritingOptions.prettyPrinted) else {
return nil
}
let decodedData = try self.decode(type, from: jsonData)
return decodedData
}

现在像这样调用它:

guard let dataObj = try? JSONDecoder().decodedObject(OrgData.self, dictionaryData: data) else {
print("Error: Couldn't decode data ")
return
}