发送json状态响应的正确方式

Question

如何发送状态码的json响应。

我的代码

func getUser(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Content-Type", "application/json")
var user []User
result := db.Find(&user)
json.NewEncoder(w).Encode(result)
}

我现在的结果:

[
{
"name" : "test",
"age" : "28",
"email":"[e-mail]"
},
{
"name" : "sss",
"age" : "60",
"email":"[e-mail]"
},
{
"name" : "ddd",
"age" : "30",
"email":"[e-mail]"
},
]

但是我需要像这样用status代码发送响应

{
status : "success",
statusCode : 200,
data : [
{
"name" : "test",
"age" : "28",
"email":"[e-mail]"
},
{
"name" : "sss",
"age" : "60",
"email":"[e-mail]"
},
{
"name" : "ddd",
"age" : "30",
"email":"[e-mail]"
},
]
}

Answer 1

如果你想要不同的json，传递一个不同的对象给Encode。

type Response struct {
Status       string `json:"status"`
StatucCode   int    `json:"statusCode"`
Data         []User `json:"data"`
}
func getUser(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Content-Type", "application/json")
var user []User
result := db.Find(&user)
json.NewEncoder(w).Encode(&Response{"success", 200, result})
}

或者使用map:

json.NewEncoder(w).Encode(map[string]interface{}{
"status": "success", 
"statusCode": 200, 
"data": result,
})