在PHP和AJAX中注册不起作用

Question

基本上，我使用PHP和Ajax进行了登录/注册，以使用phonegap。登录是有效的，如果我试图用与现有帐户相同的电子邮件创建一个帐户，它会做出响应，但当我试图创建一个新帐户时，它会说注册失败~上面是代码

PHP代码

<?php
$con = mysqli_connect("localhost","root","", "login") or die("connection error");
$email = $_POST['email'];
$password = $_POST['password'];
if(isset($_POST['register']))
{   
$register = mysqli_num_rows(mysqli_query($con, "SELECT * FROM users WHERE email='$email'"));
if($register == 0)
{
$insert = mysqli_query($con,"INSERT INTO users (email,password) VALUES ('$email','$password')");
if($insert)                 
echo "success";
else
echo "error";
}
else if($register != 0)
echo "exist";
}
else if(isset($_POST['login']))
{
$login = mysqli_num_rows(mysqli_query($con, "SELECT * FROM users WHERE email='$email' AND password`='$password'"));
if($login != 0)
echo "success";
else
echo "error";
}
mysqli_close($con);
?>

AJAX代码//这是登录代码

$("#loginButton").click(function(){
var email= $.trim($("#email").val());
var password= $.trim($("#password").val());
$("#status").text("Authenticating...");
var loginString ="email="+email+"&password="+password+"&login=";
$.ajax({
type: "POST",crossDomain: true, cache: false,
url: url,
data: loginString,
success: function(data){
if(data == "success") {
$("#status").text("Login Success..!");
localStorage.loginstatus = "true";
window.location.href = "app.html";
}
else if(data == "error")
{
$("#status").text("Login Failed..!");
}
}
});
});
$("#registerButton").click(function(){
var email= $.trim($("#email").val());
var password= $.trim($("#password").val());
$("#status").text("Creating New Account...");
var dataString="email="+email+"&password="+password+"&register=";
$.ajax({
type: "POST",crossDomain: true, cache: false,
url: url,
data: dataString,
success: function(data){
if( data == "success")
$("#status").text("Registered Success");
else if( data == "exist")
$("#status").text("Account is already there");
else if( data == "error")
$("#status").text("Register Failed");
}
});

Answer 1

确保您在config.xml 中启用了internet访问权限

Answer 2

我花了很长时间才发现这个问题。这是一个非常简单的错误，请检查SELECT查询中的语法错误。

执行了1个查询，0个成功，1个错误，0个警告

查询：SELECT*FROM users WHERE email='[e-mail]'和密码`='123'

错误代码：1064您的SQL语法有错误；检查与您的MySQL服务器版本相对应的手册在'`='123'附近使用的语法

密码后面有一个额外的`，这会破坏查询。查询失败，导致mysqli_num_rows始终返回0。