如何在python中删除一些额外的元组和列表，并在字符串之间打印一些额外的内容

Question

bounds = reader.readtext(np.array(images[0]), min_size=0,slope_ths=0.2, ycenter_ths=0.7, height_ths=0.6,width_ths=0.8,decoder='beamsearch',beamWidth=10) 
print(bounds)

上述代码的输出为

我确实有类似的字符串格式

[([[1004, 128], [1209, 128], [1209, 200], [1004, 200]],
'EC~L',
0.18826377391815186),
([[177, 179], [349, 179], [349, 241], [177, 241]], 'OKI', 0.9966741294455473),
([[180, 236], [422, 236], [422, 268], [180, 268]],
'Oki Eleclric Industry Co',
0.8091106257361781),
([[435, 243], [469, 243], [469, 263], [435, 263]], 'Ltd', 0.9978489622393302),
([[180, 265], [668, 265], [668, 293], [180, 293]],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan',
0.6109240973537998),
([[180, 291], [380, 291], [380, 318], [180, 318]],
'Tel [phone]',
0.9406430290171053)]

如何编写一个python代码，打印与下面类似的上面的格式：

[1004, 128, 1209, 128, 1209, 200, 1004, 200], 
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263], 
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel [phone]'

有人能帮我吗

Answer 1

我想我会为这个一行式解决方案做出贡献。

print("n##################n".join(("{},n'{}'".format([x for item in items[0] for x in item], items[1])) for items in bounds))

它产生的格式与询问者的愿望完全相同：

[1004, 128, 1209, 128, 1209, 200, 1004, 200],
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263],
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel [phone]'

Answer 2

如果我理解正确：

for l, s, _ in bounds:
print([lll for ll in l for lll in ll])
print(s)
print('##################')

输出：

[1004, 128, 1209, 128, 1209, 200, 1004, 200]
EC~L
##################
[177, 179, 349, 179, 349, 241, 177, 241]
OKI
##################
[180, 236, 422, 236, 422, 268, 180, 268]
Oki Eleclric Industry Co
##################
[435, 243, 469, 243, 469, 263, 435, 263]
Ltd
##################
[180, 265, 668, 265, 668, 293, 180, 293]
4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan
##################
[180, 291, 380, 291, 380, 318, 180, 318]
Tel [phone]
##################

Answer 3

另一种解决方案

from itertools import chain
for numbers, description, _ in bounds:
numbers = list(chain(*numbers))
print(f"{numbers},n"
f"'{description}'n"
"##################")

输出：

[1004, 128, 1209, 128, 1209, 200, 1004, 200],
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263],
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel [phone]'
##################