我有23个html文件，其中包含相同表格格式的数据，我想创建所有文件的数据帧，并合并到一个大数据帧中进行进一步分析，下面是代码，
import glob
import pandas as pd
all_rec = glob.glob('D:python*.html')
#print(all_rec)
list_data = []
for filename in all_rec:
data = pd.read_html(filename)
list_data.append(data)
list_data # sample output from t files
[[ start_time user_host query_time
0 2020-02-19 07:01:56.411155 lrdba[lrdba] @ localhost [] 00:01:55.299187
1 2020-02-20 07:01:56.005284 lrdba[lrdba] @ localhost [] 00:01:54.210222
db sql_text
0 kvb call PROC_PROCESSINGSUMMARY(null,null)
1 kvb call PROC_PROCESSINGSUMMARY(null,null) ],
[ start_time user_host query_time
0 2020-02-19 07:01:56.411155 lrdba[lrdba] @ localhost [] 00:01:55.299187
1 2020-02-20 07:01:56.005284 lrdba[lrdba] @ localhost [] 00:01:54.210222
db sql_text
0 kvb call PROC_PROCESSINGSUMMARY(null,null)
1 kvb call PROC_PROCESSINGSUMMARY(null,null) ]]
list_data =list_data[0] #when i mention this list_data[0] it show data for first file
list_data =list_data[-1] #for list_data[-1] it show data for last file for below code
pd.concat(list_data,ignore_index=True)
我想知道我应该在[]中输入什么值才能在一个大数据帧中获得所有文件的详细信息。
import glob
import pandas as pd
all_rec = glob.glob('D:python*.html')
#print(all_rec)
list_data = []
for filename in all_rec:
data = pd.read_html(filename)
list_data.append(data)
list_data # showing array of all html data
#remove this line
list_data =list_data[0]
#remove this line
list_data =list_data[-1]
pd.DataFrame(list_data).reset_index(drop=True) #replace concat with DataFrame
希望这能奏效！