字符串上的简单regex

Question

我正在开发一个简单的提及系统，在我的PHP脚本中，我需要从较大的文本中提取client:6，其中将出现一个或多个类似于@[John Doe (#6)](client:6)的@notice。

Ex。This is my text how do you like it @John and do you have any thoughts @Jane

在php中，字符串看起来像。

This is my text how do you like it @[John Doe (#6)](client:6) and do you have any thoughts @[Jane Doe (#7)](client:7)

我需要得到一个带有array('client:6','client:7')的阵列

Answer 1

是多种可能的方法之一

@[[^][]+]s*(K[^()]+

请参阅regex101.com上的演示。

---

就正则表达式而言，这可以归结为

@          # "@" literally
[         # "[" literally
[^][]+     # not "[" nor "]" as many times as possible
]s*      # followed by "]" literally + whitespaces, eventually
(         # you name it - "(" literally
K         # forget all what has been matched that far
[^()]+     # not "(" nor ")"

---

在PHP中，这可能是

<?php
$data = "This is my text how do you like it @[John Doe (#6)](client:6) and do you have any thoughts @[Jane Doe (#7)](client:7)";
$regex = "~@[[^][]+]s*(K[^()]+~";
preg_match_all($regex, $data, $matches);
print_r($matches);
?>

并且会产生

Array
(
[0] => Array
(
[0] => client:6
[1] => client:7
)
)

请参阅videone.com.上的演示

Answer 2

w+:d+应该可以工作。

句中：

这是我的文字，你喜欢它吗@John Doe(#6(和do你有什么想法@Jane Doe(#7(

它应该找到客户端：6和客户端：7。

您可以使用https://regexr.com/例如