我正试图登录一个不是超级用户的帐户,并从rest_framework 中得到一个错误
"detail": "No active account found with the given credentials"
使用自定义用户模型
models.py:
lass UserAccountManager(BaseUserManager):
def create_user(self, email, first_name, last_name, password=None):
if not email:
raise ValueError('Users must have an email')
email = self.normalize_email(email)
user = self.model(email=email, first_name=first_name, last_name=last_name)
user.set_password(password)
user.save()
return user
class CustomUser(AbstractBaseUser, PermissionsMixin ):
first_name = models.CharField(unique=True, max_length=200)
last_name = models.CharField(unique=True, max_length=200)
is_staff = models.BooleanField(default=False)
is_active = models.BooleanField(default=True)
date_joined = models.CharField(unique=True, max_length=200)
username = models.CharField(unique=True, max_length=200)
email = models.EmailField(unique=True)
User_Roles = models.ForeignKey(User_Roles, on_delete=models.CASCADE)
USERNAME_FIELD = 'username'
objects = BaseUserManager()
我检查了数据库中的密码是否被散列,但似乎不是这样
serializers.py:
class RegisterSerializer(ModelSerializer):
password2 = serializers.CharField(style={'input_type': 'password'})
class Meta():
model = CustomUser
fields = ['username', 'email', 'first_name', 'last_name', 'password', 'password2']
def save(self):
user = CustomUser(
email=self.validated_data['email'],
username=self.validated_data['username'],
first_name=self.validated_data['first_name'],
last_name=self.validated_data['last_name'],
)
password = self.validated_data['password'],
password2 = self.validated_data['password2'],
if password != password2:
raise serializers.ValidationError({'password': 'Passwords must Match'})
user.set_password(str(password))
user.save()
return user
我有一个错误,密码类型是元组而不是字符串或字节,并且
user.set_password(str(password))
似乎已经解决了我无法解决的问题,
用户是用散列密码创建和存储的,但不能登录
解决方案
删除下列行中的尾随逗号
password = self.validated_data['password'],
password2 = self.validated_data['password2'],
结果应该是
password = self.validated_data['password']
password2 = self.validated_data['password2']
解释
通过添加逗号,您将其变成一个元组,这将导致错误的发生,因为密码字段是字符串类型,而不是元组。
user.set_password(str(password))
似乎已经解决了我无法解决的问题,
这似乎解决了这个问题,但实际上它会引入另一个问题,即密码值在通过set_password()
方法中断之前将被设置为(PASSWORD,)
。