如何在将数字改为单词时实现青少年逻辑

Question

我只是想弄清楚如何为这段代码实现teen逻辑。例如：如果用户输入CCD_ 1，则输出应为CCD_。相反，我的输出是One hundred and ten five。

任何人都知道如何修复这个

public class NumberToWords {
public static void main(String[] args) {
String [] units = {"","one ","two ","three ","four ","five ","six ","seven ","eight ","nine ","ten ","eleven ","twelve ","thirteen ","fourteen ","fifteen ","sixteen ","seventeen ","eighteen ","ninteen "};
String tens[]=     {"","ten ","twenty ","thirty ","forty ","fifty ","sixty ","seventy ","eighty ","ninety "};
String hundreds =   "hundred ";
System.out.print("Number: ");
int num = In.nextInt();

while (num != -1) {
int tt = num/10;
int t  = tt%10;

if (num == 0){
System.out.print("zero ");
}
if(num<20){//till 19
System.out.println(units[num]);
}
else if(num<100){//till 99
System.out.println(tens[num/10] + ((num%10!=0) ?"":"") + units[num%10]);
}
else if (num<1000){//till 999 542
System.out.println(units[num/100]+hundreds+((num%100!= 0)?"and ":"")+tens[t]+units[num%10]);

}

System.out.print("Number: ");
num = In.nextInt();
}
if (num == -1) {
System.out.println("Done");
}
}
}

Answer 1

您将每个数字作为一个单独的数字进行计算并打印。您的程序需要通过创建这样的新函数来处理10-19的特殊情况：

// Expected that val is 0 - 99
public static String get_correct_val(int val)
{
String [] units = {"","one ","two ","three ","four ","five ","six ","seven ","eight ","nine "}
String [] specials = {"","ten ","eleven ","twelve ","thirteen ","fourteen ","fifteen ","sixteen ","seventeen ","eighteen ","ninteen "};
String tens[]=     {"","ten ","twenty ","thirty ","forty ","fifty ","sixty ","seventy ","eighty ","ninety "};
if(val < 10)
{
return units[val];
}
else if(val < 20)
{
return specials[val - 9];
}
else
{
return tens[Math.floor(val/10) % 10] + units[val % 10];
}
}

现在你可以从你的主要功能调用这个：

if(num<20){//till 19
System.out.println(units[num]);
}
else if(num<100){//till 99
System.out.println(tens[num/10] + get_correct_val(num % 100));
}
else if (num<1000){//till 999 542
System.out.println(units[num/100]+hundreds+((num%100!= 0)?"and ":"") + get_correct_val(num % 100));

}

Answer 2

我尝试了一种快速的不同方法，该方法仅限于从0到999。

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class numberWord {
public static Map<Integer, String> map = new HashMap<>();
public static void main(String[] args) {
map.put(0, "zero");
map.put(1, "one");
map.put(2, "two");
map.put(3, "three");
map.put(4, "four");
map.put(5, "five");
map.put(6, "six");
map.put(7, "seven");
map.put(8, "eight");
map.put(9, "nine");
map.put(10, "ten");
map.put(11, "eleven");
map.put(12, "twelve");
map.put(13, "thirteen");
map.put(14, "fourteen");
map.put(15, "fifteen");
map.put(16, "sixteen");
map.put(17, "seventeen");
map.put(18, "eighteen");
map.put(19, "nineteen");
map.put(20, "twenty");
map.put(30, "thirty");
map.put(40, "forty");
map.put(50, "fifty");
map.put(60, "sixty");
map.put(70, "seventy");
map.put(80, "eighty");
map.put(90, "ninty");
Scanner sc = new Scanner(System.in);
int inp = sc.nextInt();
if (inp > -1 && inp < 1000) {
compute(inp);
} else {
System.out.println("Out of scope");
}
sc.close();
}
public static void compute(int inp) {
if (inp <= 20) {
System.out.println(" " + map.get(inp));
} else if (inp > 20 && inp <= 99) {
int div = inp / 10;
int rem = inp % 10;
System.out.print(" " + map.get(div * 10));
if (rem != 0) {
System.out.print(" " + map.get(rem));
}
} else {
int div = inp / 100;
int rem = inp % 100;
System.out.print(map.get(div) + " hundred");
if (rem != 0) {
compute(rem);
}
}
}

}