将pyspark数据帧字符串列中的第一个数值获取到新列中

Question

我有一个pyspark数据帧，就像下面的输入数据一样。我想创建一个新列product1_num，它将productname列中每个记录中的第一个数字解析为一个新的列。下面是示例输出数据。就字符串分割和正则表达式匹配而言，我不确定pyspark中有什么可用的。有人能建议如何使用pyspark吗？

输入数据：

+------+-------------------+
|id    |productname        |
+------+-------------------+
|234832|EXTREME BERRY SAUCE|
|419836|BLUE KOSHER SAUCE  |
|350022|GUAVA (1G)         |
|123213|GUAVA 1G           |
+------+-------------------+

输出：

+------+-------------------+-------------+
|id    |productname        |product1_num |
+------+-------------------+-------------+
|234832|EXTREME BERRY SAUCE|             |
|419836|BLUE KOSHER SAUCE  |             |
|350022|GUAVA (1G)         |1            |
|123213|GUAVA G5           |5            |
|125513|3GULA G5           |3            |
|127143|GUAVA G50          |50           |
|124513|LAAVA C2L5         |2            |
+------+-------------------+-------------+

Answer 1

您可以使用regexp_extract:

from pyspark.sql import functions as F
df.withColumn("product1_num", F.regexp_extract("productname", "([0-9]+)",1)).show()
+------+-------------------+------------+
|    id|        productname|product1_num|
+------+-------------------+------------+
|234832|EXTREME BERRY SAUCE|            |
|419836|  BLUE KOSHER SAUCE|            |
|350022|         GUAVA (1G)|           1|
|123213|           GUAVA G5|           5|
|125513|           3GULA G5|           3|
|127143|          GUAVA G50|          50|
|124513|         LAAVA C2L5|           2|
+------+-------------------+------------+