如何将多个发布者发布到一个订阅者

Question

我需要建立一个包含多个发布者、一个代理和一个订阅者的网络。

问题：我有一个一对一选项的工作代码(一个酒吧-一个酒吧(。然而，当我运行更多的发布者时，订阅者只接收来自最后一个连接的发布者的消息，我不知道为什么会发生这种情况。

更多信息：Broker(mosquitto(在一个docker容器中工作，每个发布者都是一个单独的脚本，目标是在每个容器中运行多个docker集装箱，每个集装箱中有一个发布者，但现在我需要解决通信问题。

有人对如何调试或解决这个问题有任何线索或想法吗？

这是发布者脚本：

import time
import paho.mqtt.client as mqtt
import datetime
import random
import json
import logging
from multiprocessing import Process
CLEAN_SESSION = False

def on_connect(client, userdata, flags, rc):
logging.info(f"New connection {client}, {rc}")

def sensor(client_id):

localhost = '172.17.0.2'
port = 1883
timeout = 60
topic = "/mia/sensor"
client_id = f"sensor_{client_id}"

def check_sensor():

time.sleep(1)
rand = random.randint(0, 10)
if rand > 5:
current_time = datetime.datetime.now()
current_time = current_time.strftime('%Y-%m-%d %H:%M:%S')
return {"time": current_time, "signal": 1, "id": client_id}
else:
return 0

client = mqtt.Client(client_id, clean_session=CLEAN_SESSION)
client.on_connect = on_connect

client.connect(localhost, port, timeout)
while True:
check_info = check_sensor()
if check_info:
message_payload = json.dumps(check_info)
logging.info(message_payload)
client.publish(topic, message_payload, qos=2)
client.loop()
client.disconnect()

if __name__ == "__main__":
p = Process(target=sensor, args=(1,))
p.start()
print("new publisher created!")

这是订阅者脚本：

import paho.mqtt.client as mqtt
import paho.mqtt.subscribe as sub
import json
import logging

localhost = '172.17.0.2'
port = 1883
timeout = 60
topic = "/mia/sensor" 


def on_connect(client, userdata, flags, rc):
logging.info(f"New connection {client}, {rc}")
client.subscribe(topic, qos=2)


def on_message(client, userdata, msg):
data = json.loads(msg.payload.decode('utf-8'))

logging.debug(f"new message from {client} - {data}")
print(data)



client = mqtt.Client("python", clean_session=False)
client.on_connect = on_connect
client.on_message = on_message
client.connect_async(localhost, port, timeout)
client.loop_forever()

提前感谢

Answer 1

您的client_id必须是唯一的。检查一下。