我一直在尝试在D3js力导向可视化中突出显示连接节点。使用各种教程和Mike Bostock的工作，我已经设法突出显示了节点和链接，然而，子节点没有得到突出显示的
代码
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<style>
.links line {
stroke: #999;
stroke-opacity: 0.6;
}
.nodes circle {
stroke: #fff;
stroke-width: 1.5px;
}
text {
font-family: sans-serif;
font-size: 10px;
}
</style>
</head>
<body>
<svg width="1000" height="1000"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script>
var svg = d3.select("svg"),
width = +svg.attr("width"),
height = +svg.attr("height");
var color = d3.scaleOrdinal(d3.schemeCategory20);
var simulation = d3.forceSimulation()
.force("link", d3.forceLink().distance(function(d) { return d.distance; }).id(function(d) { return d.id; }))
.force("charge", d3.forceManyBody())
.force("center", d3.forceCenter(width / 2, height / 2));
d3.json("data.json", function(error, graph) {
if (error) throw error;
var link = svg.append("g")
.attr("class", "links")
.selectAll("line")
.data(graph.links)
.enter().append("line")
.attr("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.append("g")
.attr("class", "nodes")
.selectAll("g")
.data(graph.nodes)
.enter().append("g")
.on("mouseover", fade(.1))
.on("mouseout", fade(1))
var circles = node.append("circle")
.attr("r", 20)
.attr("fill", function(d) { return color(d.group); })
.call(d3.drag()
.on("start", dragstarted)
.on("drag", dragged)
.on("end", dragended));
var lables = node.append("text")
.text(function(d) {
return d.id;
})
.attr('x', 6)
.attr('y', 3);
node.append("title")
.text(function(d) { return d.id; });
simulation
.nodes(graph.nodes)
.on("tick", ticked);
simulation.force("link")
.links(graph.links);
var linkedById = {};
json.links.forEach(function(d) {
linkedById[d.source.id + "," + d.target.id] = 1;
});
function neighboring(a, b) {
return linkedById[a.id + "," + b.id] || linkedById[b.id + "," + a.id] || a.id == b.id;
}
function ticked() {
link
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node
.attr("transform", function(d) {
return "translate(" + d.x + "," + d.y + ")";
})
}
function fade(opacity) {
return function(d) {
node.style("opacity", function(o) {
return neighboring(d, o) ? 1 : opacity;
});
link.style("stroke-opacity", function(o) {
return o.source === d || o.target === d ? 1 : opacity;
});
};
}
});
function dragstarted(d) {
if (!d3.event.active) simulation.alphaTarget(0.3).restart();
d.fx = d.x;
d.fy = d.y;
}
function dragged(d) {
d.fx = d3.event.x;
d.fy = d3.event.y;
}
function dragended(d) {
if (!d3.event.active) simulation.alphaTarget(0);
d.fx = null;
d.fy = null;
}
/* Scaling nodes
function mouseover() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 30);
}
function mouseout() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 20);
}
*/
</script>
</body>
</html>
Json文件格式化示例
{
"nodes": [
{"id": "A", "group": 1},
{"id": "B", "group": 1},
{"id": "C", "group": 2},
{"id": "D", "group": 2},
{"id": "E", "group": 3},
{"id": "F", "group": 3}
],
"links": [
{"source": "A", "target": "B", "value": 2, "distance": 300},
{"source": "A", "target": "C", "value": 2, "distance": 300},
{"source": "A", "target": "E", "value": 2, "distance": 300},
{"source": "B", "target": "C", "value": 2, "distance": 300},
{"source": "B", "target": "D", "value": 2, "distance": 300},
{"source": "B", "target": "F", "value": 2, "distance": 300}
]
}
我认为这与我使用命名的源和目标而不是ID有关？我看过这个http://jsfiddle.net/tristanreid/xReHA/636/
我看到的唯一区别是来源和目标的命名方式。我更喜欢使用命名的源和目标，因为我有数据集。
如有任何协助，我们将不胜感激。
提前感谢
它不起作用的唯一原因是，您调用的数据是graph，而不是json。更改以下行：
var linkedById = {};
json.links.forEach(function(d) {
linkedById[d.source.id + "," + d.target.id] = 1;
});
至
var linkedById = {};
graph.links.forEach(function(d) {
linkedById[d.source.id + "," + d.target.id] = 1;
});
您将看到，linkedById突然得到了正确的填充，相邻节点得到了正确识别，并且高亮显示工作正常。