如何在函数外继续执行程序

Question

我是python的新手，在尝试构建GUI时遇到了麻烦。我找不到从"登录"功能中提取数据的方法，这将是用户登录后创建的新TopLevel窗口。因此，我必须在"登录功能"中编写剩余的代码，但我觉得必须有其他方法。我尝试将新的顶级设置为全局，但结果是没有定义新变量。

from tkinter import *  
from tkinter import messagebox
root = Tk()
login_frame = LabelFrame(root, text = "login info").pack()
user_field = Label(login_frame, text = "user: ")
user_field.grid(row = 0,column = 0)
pass_field = Label(login_frame, text = "pass: ")
pass_field.grid(row = 1, column = 0)
user_input = Entry(login_frame)
user_input.grid(row = 0, column = 1)
pass_input = Entry(login_frame, show = "*")
pass_input.grid(row = 1, column = 1)
def login():
if user_input.get() == "user" and pass_input.get() == "user":
if messagebox.showinfo("blah", "blah") == "ok":
pass_input.delete(0, END)
user_input.delete(0, END)
root.withdraw()
**app = Toplevel()**
else:
messagebox.showerror("blah", "blah")
pass_input.delete(0, END)
user_input.delete(0, END)
login_btn = Button(login_frame, text = "LOGIN")
login_btn.grid(row = 2, column = 0)
exit_btn = Button(login_frame, text = "SAIR")
exit_btn.grid(row = 2, column = 1)    
root.mainloop()

Answer 1

您的代码正在破坏缩进。函数定义后面的行必须在函数的范围内，如下所示：

def login():
if user_input.get() == "user" and pass_input.get() == "user":
if messagebox.showinfo("blah", "blah") == "ok":
...

不管怎样，您都可以在函数末尾返回任何类型的数据。考虑这样暴露你的TopLevel应用程序：

return TopLevel()