C - 无法将函数的指针值返回到 main

Question

程序问题链接https://www.hackerrank.com/challenges/cut-the-sticks/problem

#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readline();
char** split_string(char*);
int* cutTheSticks(int arr_count, int* arr, int* result_count) {
int c=arr_count,min;
int result[c];
for (int k=0;k<arr_count;k++){
min = *arr;
for (int i = 0; i < c; i++) {
if (*(arr + i) < min)
min = *(arr + i);
}
int count=0;
for (int i=0; i < c; i++) {
if(min==*(arr+i))count++;
}
for (int i=0; i < c; i++) {
*(arr+i)=*(arr+i)-min;
}
int temp=0;
for(int i=0;i<c;i++){
for(int x=i;x<c;x++){
if(*(arr+i)<*(arr+x)){
temp=*(arr+i);
*(arr+i)=*(arr+x);
*(arr+x)=temp;
}
}
}
result[k]= c;
*(result_count)=*(result_count)+1;
c = c - count;
if(c==0)break;
}
return result;
}
int main()
{
FILE* fptr = fopen(getenv("OUTPUT_PATH"), "w");
char* n_endptr;
char* n_str = readline();
int n = strtol(n_str, &n_endptr, 10);
if (n_endptr == n_str || *n_endptr != '') { exit(EXIT_FAILURE); }
char** arr_temp = split_string(readline());
int* arr = malloc(n * sizeof(int));
for (int i = 0; i < n; i++) {
char* arr_item_endptr;
char* arr_item_str = *(arr_temp + i);
int arr_item = strtol(arr_item_str, &arr_item_endptr, 10);
if (arr_item_endptr == arr_item_str || *arr_item_endptr != '') { 
exit(EXIT_FAILURE); }
*(arr + i) = arr_item;
}
int arr_count = n;
int result_count;
int* result = cutTheSticks(arr_count, arr, &result_count);
for (int i = 0; i < result_count; i++) {
fprintf(fptr, "%d", *(result + i));
if (i != result_count - 1) {
fprintf(fptr, "n");
}
}
fprintf(fptr, "n");
fclose(fptr);
return 0;
}
char* readline() {
size_t alloc_length = 1024;
size_t data_length = 0;
char* data = malloc(alloc_length);
while (true) {
char* cursor = data + data_length;
char* line = fgets(cursor, alloc_length - data_length, stdin);
if (!line) { break; }
data_length += strlen(cursor);
if (data_length < alloc_length - 1 || data[data_length - 1] == 'n') { 
break; }
size_t new_length = alloc_length << 1;
data = realloc(data, new_length);
if (!data) { break; }
alloc_length = new_length;
}
if (data[data_length - 1] == 'n') {
data[data_length - 1] = '';
}
data = realloc(data, data_length);
return data;
}
char** split_string(char* str) {
char** splits = NULL;
char* token = strtok(str, " ");
int spaces = 0;
while (token) {
splits = realloc(splits, sizeof(char*) * ++spaces);
if (!splits) {
return splits;
}
splits[spaces - 1] = token;
token = strtok(NULL, " ");
}
return splits;
}

上面的代码是我从harkerbank获得的完整代码，下面是主要功能。我无法将指针值从cutTheStricks返回到main函数。

// Please store the size of the integer array to be returned in
result_count 
pointer. For example,
// int a[3] = {1, 2, 3};
//
// *result_count = 3;
//
// return a;

我没有得到任何输出，但我的逻辑是正确的。我知道有东西丢失了，所以我不能返回我的输出；我不知道哪个指针值(*result或*result_count(没有通过或者发生了什么我都搞不清楚。

Answer 1

您正在返回一个本地数组的地址，该数组的生存期以函数结束，请更改

int result[c];

至

int *result = malloc(sizeof(*result) * c);

您还在此处使用未初始化值的地址：

*(result_count)=*(result_count)+1;

更改

int result_count;

至

int result_count = 0;