使用jquery重定向登录

Question

如果有人能帮忙，我会很高兴。我正在使用jquery开发登录系统，但我遇到了问题

我想实现的是用户在登录页面上填写他们的详细信息，我将在后端使用jQuery处理它，而无需重新加载页面，我已经做到了，但现在的问题是，当他们提供的详细信息和数据库中的详细信息正确时，我想将他们重定向到另一个页面

这是我的登录表单

<form class="form-login" id="loginmyForm" method="post">
<input class="input input_auth" type="text"  name="loginemail" id="loginemail" placeholder="E-mail" required />
<span id="loginError_username" class="error error-opacit"></span>
<input class="input input_auth" type="password" name="loginpassword" id="loginpassword" placeholder="Password" required />
<span id="loginError_password" class="error error-opacit"></span>
<input type="hidden" name="source" value="login" id="source">

<button class="btn pulse input_auth" type="button" id="submitFormData" onclick="loginSubmitFormData();" value="Submit">Login</button>
<div class="forgot-password">
<a id="forgotPass" href="#" class="link-btn open-modal" data-openModal="modal-recovery">Forgot your password?</a>
</div>

这是jquery代码

<script type="text/javascript">
function loginSubmitFormData() {
var loginemail = $("#loginemail").val();
var loginpassword = $("#loginpassword").val();
var source = $("#source").val();
$.post("authlogin.php", { loginemail: loginemail, loginpassword: loginpassword },
function(data) {
$('#loginresults').html(data);
$('#loginmyForm')[0].reset();
});
}
</script>

这是登录验证authlogin.php

<?php
session_start();
include 'config/info.php';
// get the details from form 
$email=$_POST['loginemail'];
$password = stripslashes($_REQUEST['loginpassword']);
$password = mysqli_real_escape_string($conn,$password);
$sql="SELECT * FROM user_info WHERE email='".$email."'";
$result = mysqli_query($conn,$sql);
$Countrow = mysqli_num_rows($result);
if ($Countrow == 1) {
$fetchrow = mysqli_fetch_assoc($result);  
$loginpassword = $fetchrow['password'];
// Verify the password here
if (password_verify($password, $loginpassword)) {
$_SESSION['email'] = $email;
//setcookie('username', $adminID, time() + (86400 * 30), "/"); 
$date = date('Y-m-d H:i:s');
$ActivityStmt = "INSERT INTO login_activity (`email`, `last_login`, `browser`, `os`, `ip_address`) VALUES('".$email."', '".$date."', '".$gen_userBrowser."', '".$gen_userOS."', '".$gen_userIP."')";
$ActivityResult = mysqli_query($conn, $ActivityStmt);
echo 'Login Successfully! <a href="account" style="color: green;">Click to proceed</a>';
exit();
}
else{
echo 'Incorrect Password';
exit();
}
}
else{
echo 'User does not exit';
exit();
}
?>

我试过使用

header('Location: account'); 

和

window.location.href = "account";

在会话被保存但没有工作后，请谁能帮助我如何完成

Answer 1

您应该尝试在代码部分替换jQuery代码和PHP代码，它肯定对您有效：

<script type="text/javascript">
function loginSubmitFormData() {
var loginemail = $("#loginemail").val();
var loginpassword = $("#loginpassword").val();
var source = $("#source").val();
$.post("authlogin.php", { loginemail: loginemail, loginpassword: loginpassword },
function(data) {
var data = jQuery.parseJSON( data );
console.log(data);
$('#loginresults').html(data.message);
if(data.redirect_url){
window.location.href = data.redirect_url;
}
$('#loginmyForm')[0].reset();
});
}
</script>
<?php
session_start();
include 'config/info.php';
// get the details from form 
$email=$_POST['loginemail'];
$password = stripslashes($_REQUEST['loginpassword']);
$password = mysqli_real_escape_string($conn,$password);
$sql="SELECT * FROM user_info WHERE email='".$email."'";
$result = mysqli_query($conn,$sql);
$Countrow = mysqli_num_rows($result);
if ($Countrow == 1) {
$fetchrow = mysqli_fetch_assoc($result);  
$loginpassword = $fetchrow['password'];
// Verify the password here
if (password_verify($password, $loginpassword)) {
$_SESSION['email'] = $email;
//setcookie('username', $adminID, time() + (86400 * 30), "/"); 
$date = date('Y-m-d H:i:s');
$ActivityStmt = "INSERT INTO login_activity (`email`, `last_login`, `browser`, `os`, `ip_address`) VALUES('".$email."', '".$date."', '".$gen_userBrowser."', '".$gen_userOS."', '".$gen_userIP."')";
$ActivityResult = mysqli_query($conn, $ActivityStmt);
$message = 'Login Successfully!';

$response = array(
'message' => $message,
'redirect_url' => 'https://www.example.com',
);

exit();
}
else{
$message = 'Incorrect Password';
$response = array(
'message' => $message
);
exit();
}
}
else{
$message = 'User does not exit';
$response = array(
'message' => $message,
);
exit();
}

echo json_encode( $response);
?>