如何在JavaScript中捕获异步错误

Question

在调用函数时是否有忽略异步错误的方法？

同步

function synchronous() {
console.log('Nice feature');
throw new Error('Async Error');
}
try {
synchronous();
console.log('Succeeded');
} catch (e) {
console.log('Caught');
}

控制台输出：
Nice feature
Caught

异步

async function asynchronous() {
console.log('Nice feature');
throw new Error('Async Error');
}
try {
asynchronous();
console.log('Succeeded');
} catch (e) {
console.log('Caught');
}

控制台输出：
Nice feature
Uncaught (in promise) Error: Async Error at asyncFunc

Answer 1

两个选项：

(async () => {
try {
await asynchronous();
console.log('Succeeded');
} catch (e) {
console.log('Caught');
}
});

或

asynchronous()
.then(r => {
console.log('succeeded');
})
.catch(e => {
console.log('caught');
});

Answer 2

我不确定这是否回答了你的问题，但如果"等待"；对于调用asynchronous((函数的结果，不会发生错误