我想创建"Year"列,从2000年到2018年,每12行重复一次每年的值,如下所示:
1 2000
2 2000
3 2000
4 2000
5 2000
6 2000
7 2000
8 2000
9 2000
10 2000
11 2000
12 2000
1 2001
2 2001
3 2001
4 2001
5 2001
6 2001
7 2001
8 2001
9 2001
10 2001
11 2001
12 2001
这应该做到:
df = pd.DataFrame({'Year': [year for year in range(2000, 2019)]})
df = df.loc[df.index.repeat(12)]
您也可以重置索引:
df = df.loc[df.index.repeat(12)].reset_index(drop=True)
这样?
for year in range(2000, 2019):
for month in range(1, 13):
print(month, "t", year)
输出:
1 2000
2 2000
3 2000
4 2000
5 2000
...
...
...
7 2018
8 2018
9 2018
10 2018
11 2018
12 2018
你的意思是这样的吗:
Year = []
for i in range(12*19):
Year.append(2000+int(i/12))
print(Year)
返回[2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018]