Python中使用Decode进行XML解析

Question

我试图读取的XML文件以b':开头

b'<?xml version="1.0" encoding="UTF-8" ?><root><property_id type="dict"><n53987 type="int">54522</n53987><n65731 type="int">66266</n65731><n44322 type="int">44857</n44322><n11633 type="int">12148</n11633><n28192 type="int">28727</n28192><n69053 type="int">69588</n69053><n26529 type="int">27064</n26529><n4844 type="int">4865</n4844><n7625 type="int">7646</n7625><n54697 type="int">55232</n54697><n6210 type="int">6231</n6210><n26710 type="int">27245</n26710><n57915 type="int">58450</n57915
import xml.etree.ElementTree as etree    
tree = etree.decode("UTF-8").parse("./property.xml")  

如何解码此文件？然后读dict类型？

Answer 1

所以你可以尝试，但这会返回一个元素实例

import ast
import xml.etree.ElementTree as etree

tree = None 
with open("property.xml", "r") as xml_file:
f = xml_file.read()

# convert string representation of bytes back to bytes
raw_xml_bytes= ast.literal_eval(f)

# read XML from raw bytes
tree = etree.fromstring(raw_xml_bytes)

另一种方法是读取文件并将其完全转换为字符串文件，然后再次重读，这将返回一个ElementTree实例。您可以使用以下方法实现这一点：

tree = None
with open("property.xml", "r") as xml_file:
f = xml_file.read()

# convert string representation of bytes back to bytes
raw_xml_bytes= ast.literal_eval(f)
# save the converted string version of the XML file
with open('output.xml', 'w') as file_obj:
file_obj.write(raw_xml_bytes.decode())
# read saved XML file 
with open('output.xml', 'r') as xml_file:
tree = etree.parse(f)

Answer 2

打开并读取xml文件将返回字节类型的数据，该文件具有.decode((方法(参见。https://docs.python.org/3/library/stdtypes.html#bytes.decode)。您可以使用适当的编码名称执行以下操作：

my_xml_text = xml_file.read().decode('utf-8')