在三维空间中垂直于父div旋转子div

Question

html {
font-size: 0.7rem;
}
div div {
top: 5rem;
background-color: #444;
transform-origin: top center;
}
.rotate_x {
animation-name: rotate_x;
}
@keyframes rotate_x {
0% {
transform: rotateX( 0deg );
}
100% {
transform: rotateX( 360deg );
}
}
.rotate_y {
animation-name: rotate_y;
}
@keyframes rotate_y {
0% {
transform: rotateY( 0deg );
}
100% {
transform: rotateY( 180deg );
}
}

<style>
* {
box-sizing: border-box;
margin: 0;
padding: 0;
animation-duration: 5s;
animation-iteration-count: infinite;
animation-timing-function: linear;
}
html, body {
display: flex;
justify-content: center;
align-items: center;
height: 100%;
width: 100%;
}
body {
perspective: 5rem;
}
div {
position: relative;
top: -1.5rem;
width: 5rem;
height: 5rem;
background-color: #222;
border-radius: 0.5rem;
}
</style>
<div class='rotate_y'>
<div class='rotate_x'>
</div>
</div>

灰色底部div似乎没有如预期的那样垂直于黑色顶部div旋转出去。相反，底部的灰色div显示为收缩，直到它具有负值并反转。期望的结果是底部灰色CCD_ 3像在铰链上一样向上旋转；在三维空间中制作"L"形在它一路上升并翻转过来在另一边做同样的事情之前。当父div旋转360度时。

如何使底部div在与其父div连接时创建一个"L"形状？

Answer 1

您需要设置transform-style并使透视图更大一点：

html {
font-size: 0.7rem;
}
div div {
top: 5rem;
background-color: #444;
transform-origin: top center;
}
.rotate_x {
animation-name: rotate_x;
}
@keyframes rotate_x {
0% {
transform: rotateX( 0deg );
}
100% {
transform: rotateX( 360deg );
}
}
.rotate_y {
animation-name: rotate_y;
transform-style:preserve-3d; /* HERE */
}
@keyframes rotate_y {
0% {
transform: rotateY( 0deg );
}
100% {
transform: rotateY( 180deg );
}
}

<style>
* {
box-sizing: border-box;
margin: 0;
padding: 0;
animation-duration: 5s;
animation-iteration-count: infinite;
animation-timing-function: linear;
}
html, body {
display: flex;
justify-content: center;
align-items: center;
height: 100%;
width: 100%;
}
body {
perspective: 15rem;
}
div {
position: relative;
top: -1.5rem;
width: 5rem;
height: 5rem;
background-color: #222;
border-radius: 0.5rem;
}
</style>
<div class='rotate_y'>
<div class='rotate_x'>
</div>
</div>